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4 years ago

How do you answer this?!!

Mathematics

1 answer:

lesya692 [45]4 years ago

6 0

Yes, It is reasonable. I think this because you are dealing with 60 blocks, and out of every 5 blocks there are 3 red. 5 goes into 60 12 times. 3 multiplied by 12 is 36. 36 is more than 32. So, I think that it is reasonable. If this explanation didn't make sense, then feel free to ask for more. I hope this helped!

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The area of a rectangle is 35 ft squared , and the length of the rectangle is 3 ft more than twice the width. find the dimension

andrey2020 [161]

Are there any answer choices

7 0

3 years ago

Simplify 3/5a * 1/a^2

slamgirl [31]

Multiplied: <span>3/5a
Simplified: Also ^ 3/5a</span>

4 0

4 years ago

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The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop

Anettt [7]

Answer:

a. $\frac{1}{15}$

b. $\frac{2}{5}$

c. $\frac{14}{15}$

d. $\frac{8}{15}$

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

a. Favorable cases for Both the laptops to be selected = $_2C_2$ = 1

Total number of cases = 15

Required probability is $\frac{1}{15}$ .

b. Favorable cases for both the desktop machines selected = $_4C_2=6$

Total number of cases = 15

Required probability is $\frac{6}{15} = \frac{2}{5}$ .

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

2. Both desktop:

Favorable cases = $_4C_2=6$

Total number of favorable cases = 8 + 6 = 14

Required probability is $\frac{14}{15}$ .

d. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

Total number of cases = 15

Required probability is $\frac{8}{15}$ .

8 0

4 years ago

Please help me out with this equation!<br> i will mark as brainliest

Natali [406]

Answer: Choice D

y = -(x - 2)^2 + 7

===========================================================

Explanation:

The highest point is (2, 7) so this is the vertex.

In general, the vertex is (h, k). We can say that h = 2 and k = 7.

The vertex form

y = a(x-h)^2 + k

updates to

y = a(x-2)^2 + 7

----------------

Note that the graph goes through (0,3) which is the y intercept. Plug those x,y coordinates into the equation above to solve for 'a'

y = a(x-2)^2 + 7

3 = a(0-2)^2 + 7

3 = a(-2)^2 + 7

3 = a(4) + 7

3 = 4a + 7

4a+7 = 3

4a = 3-7

4a = -4

a = -4/4

a = -1

----------------

Therefore, we have

y = a(x-2)^2 + 7

update to

y = -1(x-2)^2 + 7

which is the same as

y = -(x - 2)^2 + 7

and that's why the answer is choice D

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3 years ago

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Vsevolod [243]

Answer:

144

Step-by-step explanation:

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4 years ago