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Semmy [17]
3 years ago
15

Factor the following polynomial completely 2b^3 −18b

Mathematics
1 answer:
astraxan [27]3 years ago
3 0
I believe the answer is:
2b x (b-3) x (b+3)

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The populations P (in thousands) of a certain city from 2000 through 2007 can be modeled by P = 1674.7e^kt, where t represents t
Makovka662 [10]

Answer:

k = 0.02278

Step-by-step explanation:

Given that:

The population P = 1674.7e^kt

where;

t  represents the year,

if year 2000 represents t = 0

Then, the year 2007 represents = 7; &

year 2006 represents = 6

In 2006, population recorded in the city was about 1,920 thousand

Therefore;

1920 =  1674.7e^{(k\times 6)

Taking the logarithm of both sides, we get:

\mathtt{ In}(1920) = \mathtt{ In} ( 1674.7)+ 6k

7.560080465= 7.423389324 + 6k

7.560080465 -  7.423389324 = 6k

0.136691141 = 6k

k = 0.136691141/6

k ≅ 0.02278

5 0
3 years ago
URGENT!
klio [65]
1 dozen = 12........so 12 dozen eggs is (12 * 12) = 144 eggs

she sold 5/6 of the eggs.....so she sold : 5/6 * 144 = 720/6 = 120 eggs
she gave her friends (144 - 120) = 24 eggs

(a) 12x = 120.....with x being the number of dozens of eggs
        x = 120/12
        x = 10 <== she gave away 10 dozen eggs

(b) she sold a dozen for 4.50....
     4.50x = E .......x = the number of dozens of eggs sold and E = total             earned. She sold 10 dozen...so sub in 10 for x
     4.50(10) = E
    45 = E <=== she earned $ 45 from the eggs she sold
     
7 0
4 years ago
Read 2 more answers
(2+5i) - (-6+3i) <br> and please show work
Alenkasestr [34]
2+5i+6-3i

It is 8+2i
5 0
3 years ago
Read 2 more answers
Which expression is equivalent to the expression given below?
erica [24]

Step-by-step explanation:

- 35/10(2-15n/10) 145n/10 - 7 - 6n

-70/10 +35*15n/100.145n/10 -7-6n

-7 + 525n/100.145n/10 -7- 6n

-14 +5.25n .14.5n -6n

-14 +76.125n^2 -6n is final answer

7 0
3 years ago
Central angle AOB and inscribed angle ACB intercept the same arc. Concave polygon AOBC is formed. The sides of central angles wi
Westkost [7]

The sides of central angles will=always be congruent.

 

The sides of inscribed angles will=sometimes be congruent.

4 0
3 years ago
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