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2 years ago

5

A model rocket is launch from a platform 17 feet high in the initial velocity is 40 ft The path of the rocket is modeled by the

equation 16x^2 +40X +17=0 When does the rocket land

1 answer:

Katarina [22]2 years ago

6 0

Answer:

It will be in the air until P(x) is zero.

P(x) = -16x2 + 32x = -16x(x - 2)

P(x) = 0 ⇒ x = 0 or x = 2

It starts on the ground at x = 0, so the total time in the air must be x = 2 seconds.

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3 years ago

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2 years ago

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Step-by-step explanation:

Theory :

Equation of line is given as y = mx + c.

Where, m is slope and c is y intercepted.

Slope of given line : y = $\frac{2}{3}$ x+1 is m= $\frac{2}{3}$

We know that line : y = $\frac{2}{3}$ x+1 is parallel to equation of target line.

therefore, slope of target line will be $\frac{2}{3}$ .

we write equation of target line as y= $\frac{2}{3}$ x+c

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