A model rocket is launch from a platform 17 feet high in the initial velocity is 40 ft The path of the rocket is modeled by the
equation 16x^2 +40X +17=0 When does the rocket land
1 answer:
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Answer:
2x−5y=12
y = 2/5x + −12/5
Answer is x = 5/2y + 6 because....
First, Add 5y to both sides.
2x − 5y + 5y = 12 + 5y
Then, Divide both sides by 2.
Therefor, your answer is going to be x = 5/2y + 6
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