A model rocket is launch from a platform 17 feet high in the initial velocity is 40 ft The path of the rocket is modeled by the
equation 16x^2 +40X +17=0 When does the rocket land
1 answer:
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Answer:
y = - x +
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (2, - 3) and (x₂, y₂ ) = (- 1, 4)
m = =
= -
, thus
y = - x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (- 1, 4), then
4 = + c ⇒ c = 4 -
=
y = - x +
← equation of line