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Nitella [24]
2 years ago
15

Please help me answer the question in the image

Mathematics
2 answers:
Julli [10]2 years ago
6 0

Hey there!

Answer: \Rightarrow \boxed {\sf{\frac{2x}{(x+2)}}}

<em><u>Solving steps:-</u></em>

\rightarrow\sf{\frac{ {2x}^{2}  + 8x}{ {x}^{2}  + 6x + 8} }

\rightarrow\sf{\frac{ 2x(x + 4)}{ {x}^{2}  + 4x +2x +  8} }

\rightarrow\sf{\frac{ 2x(x + 4)}{ x  (x + 4) +2(x +  4)} }

\rightarrow\sf{\frac{ 2x\sout{(x + 4)}}{  \sout{(x + 4)} (x +  2)} }

\rightarrow\sf{\frac{ 2x}{   (x +  2)} }

~Done~

Gnesinka [82]2 years ago
3 0

Answer:

2x/x+2

Step-by-step explanation:

Factor out 2x in the numerator

Then you get: 2x(x+4)

Factor the denominator

Two numbers that multiply to 8 and add to 6(2 and 4)

So you get: (x+2)(x+4)

Now you have: (2x(x+4))/(x+2)(x+4)

Simplify by cancelling the x+4

2x/x+2

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Plz i need help and plz explain
Montano1993 [528]

\frac{ {x}^{2}  - 7x + 12}{ {x}^{2} - x - 12 }  \\  =  \frac{ {x}^{2} - 4x - 3x + 12 }{ {x}^{2} - 4x + 3x - 12 }  \\  =  \frac{x(x - 4) - 3(x - 4)}{x(x - 4) + 3(x - 4)}  \\  =  \frac{(x - 3)(x - 4)}{(x + 3)(x - 4)}  \\  =  \frac{x - 3}{x + 3}

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(x + 3)(x - 4) ≠ 0

x ≠ -3 or x ≠ 4

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3 years ago
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