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adoni [48]
3 years ago
7

PLZ HELP The slope of the graph of a direct variation function is 4. What is the equation of the function? y = 4 x + 1 y = 1/4 x

y = -4 x y = 4 x
Mathematics
2 answers:
Drupady [299]3 years ago
8 0

Answer:

d. y = 4 x

Step-by-step explanation:

A direct variation

1. has no y-intercept

2. has a constant positive slope.

Out of

y = 4 x + 1   [has y-intercept of +1]

y = 1/4 x       [direct variation with a slope of 1/4, not 4]

y = -4 x        [has a negative slope]

y = 4 x         [direct variation with slope of 4]

Delicious77 [7]3 years ago
3 0

Answer:

y = 4x

Step-by-step explanation:

A direct variation is written in the form

y = kx where k is the constant of variation  ( or the slope)

y = 4x

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Answer:

a)  See attachment 1.

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c)  See attachment 2.

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Step-by-step explanation:

<h3><u>Part (a)</u></h3>

See attachment 1.  The line of best fit is shown in red.

<h3><u>Part (b)</u></h3>

The quantities the student should graph in order to produce a <u>linear relationship</u> between the two quantities are t² and D.

<h3><u>Part (c)</u></h3>

Make a table of values of t² and D:

\begin{array}{|l|l|l|l|l|l|}\cline{1-6} \rm t^2& 0.0196& 0.1024& 0.2116 & 0.3481& 0.3969\\\cline{1-6} \rm D & 0.10 & 0.50& 1.00 & 1.70 & 2.00\\\cline{1-6}\end{array}

<u>Plot</u> a graph of D against t² and draw a line of best fit (see attachment 2).

<h3><u>Part (d)</u></h3>

From inspection of the graph, the line of best fit passes through the origin (0, 0) and (0.1024, 5.0).  Therefore, use these two points to find the slope of the line:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{0.5-0}{0.1024-0}=4.8828125...\:\rm m/s^2

Therefore:

\rm \implies \dfrac{1}{2}g=4.8828125...\:\rm m/s^2

\rm \implies g=2 \cdot 4.8828125...\:\rm m/s^2

\rm \implies g=9.8\:\rm m/s^2\:(1\:d.p.)

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