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adoni [48]
3 years ago
7

PLZ HELP The slope of the graph of a direct variation function is 4. What is the equation of the function? y = 4 x + 1 y = 1/4 x

y = -4 x y = 4 x
Mathematics
2 answers:
Drupady [299]3 years ago
8 0

Answer:

d. y = 4 x

Step-by-step explanation:

A direct variation

1. has no y-intercept

2. has a constant positive slope.

Out of

y = 4 x + 1   [has y-intercept of +1]

y = 1/4 x       [direct variation with a slope of 1/4, not 4]

y = -4 x        [has a negative slope]

y = 4 x         [direct variation with slope of 4]

Delicious77 [7]3 years ago
3 0

Answer:

y = 4x

Step-by-step explanation:

A direct variation is written in the form

y = kx where k is the constant of variation  ( or the slope)

y = 4x

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Order these fractions from least to greatest 6/8, 3/8, 5/8
Bess [88]

Answer:

3/8, 6/8, 5/8

Step-by-step explanation:

that is the right answer

8 0
3 years ago
If s varies inversely as<br>t^2, and s = 10 when t=2, find s when t is 10.​
shepuryov [24]

We apply our knowledge in variation.

The solution can be seen in the photo

6 0
3 years ago
Which of the following data sets has a range of 40?
jeka94

Answer:

The second answer - 40, 10, 20, 50

Step-by-step explanation:

Range is the difference between the largest and smallest number in a data set. The biggest and smallest numbers in the data set are 50 and 10, respectively. 50 - 10 = 40.

4 0
3 years ago
Read 2 more answers
mike drove to a frineds house at the rage of 40 mph. he returned hoke by the dsne route at 45 mph the driving time for the round
wolverine [178]

Let the distance be x miles

Time = Distance / speed

Time taken by Mike to go to his friend's house = x / 40 hours

Time taken by him to return = x / 45 hours

Total time = x / 40 + x / 45 = 4 hours

= 9x + 8x = 1440 miles

17x = 1440

= x = 1440 ÷ 7

= x = 84.706

Time taken to return home = 84.706 /45= 1.882 hours .

Therefore , Mike took 1.882 hours to reach home .

8 0
3 years ago
Find the slope of the line tangent to the
g100num [7]
Ln(xy) - 2x =0

slope of the tangent line = derivative of the function

[ln(xy)]' = [2x]'

[1/(xy)] [y + xy'] = 2

y + xy' = 2(xy)

xy' = 2xy - y =y(2x-1)

y' = y(2x-1)/x

Now use x = -1 to find y and after to find y'

ln(xy) = 2x
x=-1
ln(-y) =-2

-y = e^-2

y = - e^-2

y' = [-e^-2][2(-1)-1]/(-1) = [e^-2](-2-1)= [e^-2](-3) = - 3e^-2

Answer: option 6. from the list
8 0
3 years ago
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