All categories

3 years ago

Choose the correct simplification of the expression b5 ⋅ b4. b b9 b20 b−1

Mathematics

2 answers:

ratelena [41]3 years ago

7 0

For this case we have the following expression:

$b ^ 5b ^ 4$

We must consider the following property of the exponents.

In multiplication, when we have the same base, the exponents are added.

Rewriting the given expression we have:

$b ^ 5b ^ 4 = b ^ {(5 + 4)}\\b ^ 5b ^ 4 = b ^ 9$

Answer:

the correct simplification of the expression is:

$b ^ 5b ^ 4 = b ^ 9$

Romashka-Z-Leto [24]3 years ago

7 0

When multiplying like terms, you add the exponents:

b^5 · b^4 = b^(5+4) = b^9

FYI - when dividing like terms, subtract the exponents.

The only time we multiply exponents is when they distribute across parentheses:
(x³)² = x^6

You might be interested in

lab scale known to have a standard deviation of 0.001gram, speimen weghtted 8 times. average weiht is 4.1602 gram. what is 99% c

gtnhenbr [62]

Answer:

$99\% CI=4.1602 \pm 0.0009$

Step-by-step explanation:

From the question we are told that:

Sample size $n=8$

Mean $\=x=4.1602$

Standard deviation $\sigma=0.001gram$

Generally 99\% confidence from table is mathematically given by

$99\% CI=4.1602 \pm *2.576*\frac{0.001}{\sqrt{{8}}}$

$P(-z$

$Z_{\alpha/2}=2.576$

Generally the equation for 99\% confidence level (CI) is mathematically given by

$99\% CI=\=x \pm Z_{\alpha/2*\frac{\sigma}{\sqrt{{n}}}$

$99\% CI=4.1602 \pm 0.0009$

5 0

3 years ago

What is the value of y for the point with an x-value of 5?

crimeas [40]

-2y4 that is the answe

8 0

3 years ago

Un estudiante debe recorrer dos tercios de kilómetro para llegar al colegio, si avanza medio kilómetro en bus y lo demás a pie ¿

Murljashka [212]

Answer:

Al estudiante le falta caminar $\frac{1}{3}$ de kilómetro.

Step-by-step explanation:

Un estudiante debe recorrer dos tercios de kilómetro para llegar al colegio. Dos tercios equivale a la fracción $\frac{2}{3}$ .

El estudiante avanza medio kilómetro en bus. Un medio equivale a la fracción $\frac{1}{2}$ , por lo tanto un medio es la mitad de una cantidad. Para calcular la distancia recorrida en bus se realiza la siguiente multiplicación:

$\frac{1}{2} *\frac{2}{3}$

Resolviendo:

$\frac{1}{2} *\frac{2}{3} =\frac{1*2}{2*3} =\frac{2}{6} =\frac{1}{3}$

Entonces, la distancia recorrida en bus es $\frac{1}{3}$ de kilómetro.

Para calcular la distancia recorrida a pie se calcula la diferencia entre la distancia total a recorrer por el estudiante y la distancia recorrida en bus. Esto es:

$\frac{2}{3} - \frac{1}{3}$