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AleksandrR [38]
3 years ago
8

Choose the correct simplification of the expression b5 ⋅ b4. b b9 b20 b−1

Mathematics
2 answers:
ratelena [41]3 years ago
7 0

For this case we have the following expression:

b ^ 5b ^ 4

We must consider the following property of the exponents.

  • <em>In multiplication, when we have the same base, the exponents are added. </em>

Rewriting the given expression we have:

b ^ 5b ^ 4 = b ^ {(5 + 4)}\\b ^ 5b ^ 4 = b ^ 9

Answer:

the correct simplification of the expression is:

b ^ 5b ^ 4 = b ^ 9


Romashka-Z-Leto [24]3 years ago
7 0
When multiplying like terms, you add the exponents:

b^5 · b^4 = b^(5+4) = b^9

FYI - when <em>dividing </em>like terms, subtract the exponents.

The only time we multiply exponents is when they distribute across parentheses:
(x³)² = x^6
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Lena [83]

Answer:

Exponential form: y = x^½

Step-by-step explanation:

Given

log_xy= \frac{1}{2}

Required:

The exponential form

To convert to an exponential function, we have to take exponents of both sides using the base of the logarithm function.

This gives us

x^{log_xy}= x^\frac{1}{2}

Since the base of the exponential function and the logarithm is the same (x), they'll cancel out one another

This leaves us with

y= x^\frac{1}{2}

Hence, the exponential form of the expression

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3 years ago
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PIT_PIT [208]

In the smaller triangle, let y be the length of the smallest leg. Then the smallest leg in the larger triangle is 14-y.

Within the scope of the smaller triangle, we have y such that

x^2+y^2=13^2\implies y=\sqrt{13^2-x^2}

Then within the larger the triangle, we would have

x^2+(14-y)^2=15^2\iff x^2+\left(14-\sqrt{13^2-x^2}\right)^2=15^2

Now we can solve for x:

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Answer:

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Step-by-step explanation:

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