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makvit [3.9K]
3 years ago
12

I really need help plz

Mathematics
1 answer:
yanalaym [24]3 years ago
6 0
The slope is m=undefined
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Solve the inequality.<br>2(4+2x)25x+5<br>​
Wewaii [24]
2(4+2x)25x+5 = 300x + 5
2(4+2)•25x+5
2(4+2)•25x=300x
= 300x + 5
6 0
3 years ago
Please help picture shown and show workkkk
tankabanditka [31]
1)
Area of largest circle - 2 * Area of one smaller circle = Area of the shaded region

AE = diameter of large circle = 48cm
radius of larger circle = diameter / 2 = 48cm / 2 = 24cm

4 circles fit across the diameter of the circle, so the diameter of the larger circle = 4 * diameter of the smaller circle
diameter of larger circle = 48cm = 4 * diameter of the smaller circle
diameter of the smaller circle = 48cm / 4 = 12cm
radius of smaller circle = diameter / 2 = 12cm / 2 = 6cm

Area of a circle = pi * r^2

Now plug the circle area equation into the first equation:
A_{shaded}=A_{l} - 2*A_{s}\\\\A_{shaded}=[\pi (r_{l})^{2}]-2*[\pi (r_{s})^{2}]\\\\A_{shaded}=[\pi (48cm)^{2}]-2*[\pi (6cm)^{2}]\\\\A_{shaded}=2304\pi-72\pi\\\\Area\ of\ shaded\ region\ is\ 2232\pi.


2)
Area of the shaded region = 2/7 * Area of the smaller circle
Area of the unshaded region = Area of larger circle + Area of smaller circle - Area of shaded region * 2
A_{unshaded}=[\pi (r_{1})^{2}]+[\pi (r_{2})^{2}]-2*[\pi (r_{2})^{2}]*\frac{2}{7}\\\\A_{unshaded}=[\pi (10cm)^{2}]+[\pi (7cm)^{2}] -\frac{4}{7}[\pi (7cm)^{2}]\\\\A_{unshaded}=100\pi\ cm^{2}+49\pi\ cm^{2}-\frac{4*49\pi\ cm^{2}}{7}\\\\A_{unshaded}=149\pi\ cm^{2}-(4*7*\pi\ cm^{2})\\\\A_{unshaded}=149\pi\ cm^{2}-28\pi\ cm^{2}\\\\\\A_{unshaded}=121\pi\ cm^{2}
3 0
4 years ago
Please help I’ll give brainylist in return thank you
madam [21]

Answer:

to be honest I believe it is D

Step-by-step explanation:

sorry if i'm wrong

4 0
3 years ago
Read 2 more answers
8.23<br>x 37<br>61<br>14<br>19<br>In0.51​
yaroslaw [1]

Answer:

304.51.

Step-by-step explanation:

Your question is kind of confusing but I think your question is 8.23 x 37. The answer to that is 304.51.

8 0
3 years ago
Please help with 24-26
Inga [223]

24

The power 0 only affects the x. x^0 = 1

-2 * 1 = -2

25

Here everything inside the brackets is affected by the 0.

(11abx)^0 = 1 There is nothing left over.

26

(xy)^0 = 1

(pq)^0 = 1

1 - 1 = 0


3 0
3 years ago
Read 2 more answers
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