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3 years ago

TRUE or FALSE: The given function below is an exponential decay. f (x)= 4 x − 7

Mathematics

1 answer:

Valentin [98]3 years ago

5 0

Answer: im pretty sure its False

Step-by-step explanation:

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What are 5 different equation that have x=5 as a solution.

777dan777 [17]

X+6=11
X-11=-6
5x=25
2x=10
2x+15=25

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3 years ago

What is the y coordinate in the solution for the system of linear equations below

Natali5045456 [20]

Answer:

y=6

Step-by-step explanation:

use elimination by making the ys opposite in value and eliminating them from the equation so there is only variable:

-3x+2y=6

2(4x-y=2)

-3x+2y=6

8x-2y=4

Combine like terms and divide by 5 on both sides.

5x=10

x=2

Plug x in to find y:

4(2)-y=2

8-y=2

y=6

5 0

3 years ago

Which scatterplot shows the weakest negative linear correlation?

kherson [118]

Answer:

the first option, i took the test

Step-by-step explanation:

4 0

3 years ago

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Suppose you have a light bulb that emits 50 watts of visible light. (Note: This is not the case for a standard 50-watt light bul

natali 33 [55]

Answer:

0.049168726 light-years

Step-by-step explanation:

The apparent brightness of a star is

$\bf B=\displaystyle\frac{L}{4\pi d^2}$

where

<em>L = luminosity of the star (related to the Sun) </em>

<em>d = distance in ly (light-years) </em>

The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.

Hence the apparent brightness of Alpha Centauri A is

$\bf B=\displaystyle\frac{1.519}{4\pi (4.37)^2}=0.006329728$

According to the inverse square law for light intensity

$\bf \displaystyle\frac{I_1}{I_2}=\displaystyle\frac{d_2^2}{d_1^2}$

where

$\bf I_1=$ light intensity at distance $\bf d_1$

$\bf I_2=$ light intensity at distance $\bf d_2$

Let $\bf d_2$ be the distance we would have to place the 50-watt bulb, then replacing in the formula

$\bf \displaystyle\frac{0.006329728}{50}=\displaystyle\frac{d_2^2}{(4.37)^2}\Rightarrow\\\\\Rightarrow d_2^2=\displaystyle\frac{0.006329728*(4.37)^2}{50}\Rightarrow d_2^2=0.002417564\Rightarrow\\\\\Rightarrow d_2=\sqrt{0.002417564}=\boxed{0.049168726\;ly}$

Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.

7 0

3 years ago

What is 4.8 X -0.59?

melisa1 [442]

Answer:

I hope this helps you! :)

5 0

3 years ago

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