Question

The solution to the equation 2x^2+x-1=2

Answer 1

Answer:

$x=-\frac{3}{2}, x=1$

Step-by-step explanation:

$2x^2+x-1=2$

Subtract 2 from both sides and factor:

$2x^2+x-1=2\\2x^2+x-3=0\\(2x+3)(x-1)=0$

Solve each factor individually:

$2x+3=0\\2x=-3\\x=-\frac{3}{2}$

$x-1=0\\x=1$