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Genrish500 [490]
3 years ago
14

Please help :(,,,,,,???,,,,,,

Mathematics
1 answer:
nadya68 [22]3 years ago
5 0

Step-by-step explanation:

The first one (f×g)(x) is asking you what is f of x times g of x. This means you multiply the function. You can multiply by the first term (5x) then the second (3) and combine like terms.

{15x}^{2} (5x) =  {75x}^{3}   \\ 19x(5x)  = 95 {x}^{2} \\  6(5x)  = 30x

{15x}^{2} (3) = 45 {x}^{2}  \\ 19x(3) = 57x \\ 6(3) = 18

Combine like terms

{75x}^{3}  +  {95x}^{2}  +  {45x}^{2}  + 30x + 57x \\  + 18 = \\   {75x}^{3}  +  {140x}^{2}  + 87x + 18

The second one asks you to divide.

Factor out f(x):

{15x}^{2}  + 19x + 6

From dividing f(x) /g(x)

\frac{ {15x}^{2} + 19x + 6 }{5x + 3}

To

\frac{(5x + 3)(3x + 2)}{5x + 3}

Cancel like terms since (5x+3) is on top and bottom of fraction.

You get 3x+2

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How many solutions does this linear system have? y = y equals StartFraction 2 over 3 EndFraction x plus 2. X 2 6x – 4y = –10 one
nordsb [41]

The system of equations provides a unique solution(one solution) at (-0.6, 1.6).

<h2>Given to us,</h2>
  1. y=\dfrac{2}{3}x+2
  2. 6x-4y=-10

<h3>Equation 2</h3>

As we already have the value of y from equation 1, substitute its value in equation 2,

6x-4y=-10

6x-4(\dfrac{2}{3}x+2)=-10

6x-\dfrac{8}{3}x-8=-10

\dfrac{6x}{1}-\dfrac{8}{3}x=-10+8

\dfrac{6x\times 3}{1\times 3}-\dfrac{8}{3}x=-2

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x=\dfrac{-6}{10} \\\\x=-0.6

<h3>Equation 1,</h3>

y=\dfrac{2}{3}x+2

substitute the value of x in equation 1,

y=\dfrac{2}{3}(\dfrac{-6}{10})+2\\\\y = \dfrac{-2}{5}+2\\\\y= \dfrac{-2+10}{5}\\\\y = \dfrac{8}{5}\\\\y=1.6

As we can see the system of equations provides a unique solution(one solution) at (-0.6, 1.6).

Learn more about the system of equations:

brainly.com/question/12895249

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