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Genrish500 [490]
4 years ago
14

Please help :(,,,,,,???,,,,,,

Mathematics
1 answer:
nadya68 [22]4 years ago
5 0

Step-by-step explanation:

The first one (f×g)(x) is asking you what is f of x times g of x. This means you multiply the function. You can multiply by the first term (5x) then the second (3) and combine like terms.

{15x}^{2} (5x) =  {75x}^{3}   \\ 19x(5x)  = 95 {x}^{2} \\  6(5x)  = 30x

{15x}^{2} (3) = 45 {x}^{2}  \\ 19x(3) = 57x \\ 6(3) = 18

Combine like terms

{75x}^{3}  +  {95x}^{2}  +  {45x}^{2}  + 30x + 57x \\  + 18 = \\   {75x}^{3}  +  {140x}^{2}  + 87x + 18

The second one asks you to divide.

Factor out f(x):

{15x}^{2}  + 19x + 6

From dividing f(x) /g(x)

\frac{ {15x}^{2} + 19x + 6 }{5x + 3}

To

\frac{(5x + 3)(3x + 2)}{5x + 3}

Cancel like terms since (5x+3) is on top and bottom of fraction.

You get 3x+2

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A roll of wallpaper cost £7.85 richard buy 25 rolls of wallpaper estimate
joja [24]

Answer:

Step-by-step explanation:

if we're estimating ,we're going to round up to 8 since you can multiply that easier. 25 times 8 is 200 so estimation will be around 200

7 0
3 years ago
Y=2x-15 y=5x what the x equals
daser333 [38]

Answer:

16y=13x

Step-by-step explanation:

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7 0
3 years ago
What is the measure of a regular octagon?
pickupchik [31]
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7 0
4 years ago
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2/3p-14=p+13<br> How do I solve this
Aleks04 [339]
Add 14 to both sides
2/3p=p+27

Subtract p from both sides
-1/3p= 27

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7 0
4 years ago
Read 2 more answers
Which operation results in an expression equivalent to ? 23y^4 - 6y^3 + 35y^2 - 20y
Tom [10]

Answer:

D. P + Q

Explanation:

Given:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7)

Required:

Determine which operation will give an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

SOLUTION:

Perform each operation given to see which of them gives an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

Q - P:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7)

Q - P = (5y² - 4y)(3y² + 7) - (8y⁴ + 6y³ + 8y)

(5y²(3y² + 7) -4y(3y² + 7)) - (8y⁴ + 6y³ + 8y)

(15y⁴ + 35y² - 12y³ - 28y) - (8y⁴ + 6y³ + 8y)

Open parentheses

15y⁴ + 35y² - 12y³ - 28y - 8y⁴ - 6y³ - 8y

Collect like terms

15y⁴ - 8y⁴ - 12y³ - 6y³ + 35y² - 28y - 8y

7y⁴ - 18y³ + 35y² - 36y

Therefore, P - Q does not give us an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

PQ:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7) = (15y⁴ + 35y² - 12y³ - 28y)

PQ = (8y⁴ + 6y³ + 8y)(15y⁴ + 35y² - 12y³ - 28y)

=(8y⁴(15y⁴ + 35y² - 12y³ - 28y) +6y³(8y⁴ + 6y³ + 8y)(15y⁴ + 35y² - 12y³ - 28y) +8y(8y⁴ + 6y³ + 8y)(15y⁴ + 35y² - 12y³ - 28y))

= 120y⁸ . . . . .

Note: You don't need to perform this operation further anymore. It would definitely not give us the equivalent expression we are looking for. The degree of the leading term (120y⁸) is way too greater than the degree of the leading term (23y⁴) of the equivalent expression we are looking for.

Thus, PQ cannot give us an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

P - Q:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7) = (15y⁴ + 35y² - 12y³ - 28y)

P - Q = (8y⁴ + 6y³ + 8y) - (15y⁴ + 35y² - 12y³ - 28y)

Open parentheses

8y⁴ + 6y³ + 8y - 15y⁴ - 35y² + 12y³ + 28y

Collect like terms

8y⁴ - 15y⁴ + 6y³ + 12y³ - 35y² + 8y + 28y

-7y⁴ + 18y³ - 35y² + 36y

Therefore, P - Q cannot give us an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

P + Q:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7) = (15y⁴ + 35y² - 12y³ - 28y)

P + Q = (8y⁴ + 6y³ + 8y) + (15y⁴ + 35y² - 12y³ - 28y)

Open parentheses

8y⁴ + 6y³ + 8y + 15y⁴ + 35y² - 12y³ - 28y

Collect like terms

8y⁴ + 15y⁴ + 6y³ - 12y³ + 35y² + 8y - 28y

23y³ - 6y³ + 35y² - 20y

Therefore, P + Q will result in an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

The answer is D.

7 0
3 years ago
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