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Sedaia [141]
3 years ago
12

Tammys desk had 7/12 grams of dust on it she wiped away 5/12 grams of the dust how many grams of dust are left on her desk write

your answer as a fraction in simplest form
Mathematics
1 answer:
nexus9112 [7]3 years ago
7 0

Answer:

2/12

Step-by-step explanation:

7/12 -5/12 = 2/12

the number 2 can go into 2 once and 12 six times so you should get 1/6 as your answer

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Investments historically have doubled every 9 years. if you start with 2,000 investment, how much money would you have after 45
77julia77 [94]

Answer: 64,000

Equation: 2,000*2^(45/9)

4 0
3 years ago
I need help with multistep equations<br>​
Over [174]

Answer:

1 2/3 = m

Step-by-step explanation:

2/3 = m+3/5 -8/5

Combine terms

2/3 = m-5/5

2/3 = m -1

Add 1 to each side

2/3 +1 = m-1+1

2/3 +3/3 = m

5/3 = m

1 2/3 = m

4 0
3 years ago
Read 2 more answers
Find the limit, if it exists.<br> Picture provided below.
Alja [10]

The answer is 20 because you plug in x=2 into f(x)

3 \times 2 {}^{3}  + 2^{2}  - 8 = 20

7 0
3 years ago
Assume you have such a watch. if a minimum of 18.0% of the original tritium is needed to read the dial in dark places, for how m
laila [671]
Given that the half life of 3H is 12.3 years.

The amount of substance left of a radioactive substance with half life of t_{ \frac{1}{2} } after t years is given by

N(t)=N_0\left(\frac{1}{2} \right)^{ \frac{t}{t_{\frac{1}{2}} }

Therefore, the number of years it will take for 18% of the original tritinum to remain is given by

18 \% = 100 \% \left(\frac{1}{2} \right)^{ \frac{t}{12.3}} \\  \\ \Rightarrow\left(\frac{1}{2} \right)^{ \frac{t}{12.3}} =0.18 \\  \\ \Rightarrow\frac{t}{12.3}\ln\left(\frac{1}{2} \right)=\ln0.18 \\  \\ \Rightarrow\frac{t}{12.3}= \frac{\ln0.18}{\ln\left(\frac{1}{2} \right)} = \frac{-1.715}{-0.6931} =2.474\\ \\ \Rightarrow t=2.474(12.3)=30.4

Therefore, the number of <span>years that the time could be read at night is 30.4 years.</span>
5 0
3 years ago
The area of a trapezoid is 39 square millimeters. The height of the trapezoid is 8 millimeters. One of the base lengths of the t
AysviL [449]

Answer: 18 meters

Step-by-step explanation:

6 0
3 years ago
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