Answer:
4th option, (cy+b)/a
Step-by-step explanation:
By algebraic manipulation, we add b to both sides, then divide by a to isolate x.
Answer:
Area of ABCD = 959.93 units²
Step-by-step explanation:
a). By applying Sine rule in the ΔABD,


Sin∠DBA = 
m∠DBA = 
m∠DBA = 45.64°
Therefore, m∠ADB = 180° - (110° + 45.64°) = 24.36°
m∠ADB = 24.36°
c). Area of ABCD = Area of ΔABD + Area of ΔBCD
Area of ΔABD = AD×BD×Sin(
)
= 35×46Sin(12.18)
= 339.68 units²
Area of ΔBCD = BD×BC×Sin(
)°
= 46×27×(0.4994)
= 620.25 units²
Area of ABCD = 339.68 + 620.25
= 959.93 units²
The answer is I don't know because if you add them both you get 5 and 6.
About 95% of rats weight is between 2.5+2 *standard deviation=2.5+2*0.5=2.5+1=3.5 and 2.5-1=1.5 (1.5,3.5).
About 68% of rats weight is between (2.5-1*standard deviation, 2.5+1*standard deviation), (2,3).
This means that about 68 percent of rats in the city weigh between 2 pounds and 3 pounds. (solution b)