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3 years ago

PLEASE HELP I WILL GIVE YOU BRAINLIST I NEED HELP PLEASE

Mathematics

1 answer:

bearhunter [10]3 years ago

3 0

Answer:

One Solution

Step-by-step explanation:

Do distributive property

3k+6+3+7k=2k+4+3k

Combine like terms

10k+9=5k+4

Subtract 5k from 10k

5k+9=4

Subtract 9 from 4

5k=-5

Divide

k=-1

Hope this helped, Have a Wonderful Day!!

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Answer:

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Step-by-step explanation:

Given

$15(5)^2(-\frac{1}{2})^4$

Required

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$(a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......$

[Next is to solve for a and b]

From the above expression, the power of (5) is 2

Express 2 as 6 - 4

$(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......$

By direct comparison of

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

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$(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......$

We have;

$^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4$

Further comparison gives

$^nC_r = 15$

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$b^r= (-\frac{1}{2})^4$

[Solving for a]

By direct comparison of $a^{n-r} =(5)^{6-4}$

$a = 5$

$n = 6$

$r = 4$

[Solving for b]

By direct comparison of $b^r= (-\frac{1}{2})^4$

$r = 4$

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Substitute values for a, b, n and r in

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$(5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......$

Solve for $^6C_4$

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$(5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......$

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