Answer:
40951
Step-by-step explanation:
Using the principles of inclusion - Exclusion
Where C(n,r)=n!/(n-r)!r!
Total elements in the five sets including number repetition is given as (10000)×C(5, 1) =10000× 5!/(5-1)!1!=10000×5=50000
Total Number of elements in each pair including number repetition of sets is given as
=(1000) × C(5, 2) =10000
Number of elements in each triple of sets is given as
=(100) × C(5, 3) =1000
Number of elements in every four sets
=(10) × C(5, 4)=50
Number of elements in every one set
(1) × C(5, 5)=1
Therefore total number of unique elements=50000-10000+1000-50+1
=40951
9514 1404 393
Answer:
₹14000
Step-by-step explanation:
Let c represent the cost price, and m represent the marked price.
c × (1 +40%) = m
m × (1 -15%) - c = ₹1900
Using the first expression for m, the second equation becomes ...
1.40c×0.85 -c = ₹1900
0.19c = ₹1900
c = ₹1900/0.19 = ₹10000
Then the marked price was ...
m = 1.40c = 1.40×₹10000 = ₹14000
The marked price was ₹14000.
_____
The selling price was ₹11900.
Answer:
The answer is not in the options, it is 67.5
Step-by-step explanation:
135/2 = 67.5
Answer:
120(3)=x
120*3=360
x=360 min to go to the Airport by train.
Step-by-step explanation:
Answer/Step-by-step explanation:
27.
✔️Sin 23 = opp/hyp
Sin 23 = t/34
34*sin 23 = t
t = 13.3
✔️Cos 23 = adj/hyp
Cos 23 = s/34
s = 34*cos 23
s = 31.3
28.
✔️Sin 36 = opp/hyp
Sin 36 = s/5
s = 5*sin 36
s = 2.9
✔️Cos 36 = adj/hyp
Cos 36 = r/5
r = 5*cos 36
r = 4.0
29.
✔️Sin 70 = opp/hyp
Sin 70 = w/10
w = 10*sin 70
w = 9.4
✔️Cos 70 = adj/hyp
Cos 70 = v/10
v = 10*cos 70
v = 3.4
