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3 years ago

What number is 27% of 52? Round to the nearest tenth if necessary.

Mathematics

2 answers:

Fittoniya [83]3 years ago

7 0

27% of 52 is 14
Hope this helps. Brainliest?

Varvara68 [4.7K]3 years ago

6 0

Answer: 14.04

Step-by-step explanation: Rounded also to 14.00.

Please brainliest!

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Evaluate the function when x=-1 g (x) = 3x square 2 + 1 ?

finlep [7]

Answer:

Step-by-step explanation:

X = -1 so, we have:

3·1² + 1

3² + 1

9 + 1

5 0

3 years ago

A=c+(-10) Solve for c in terms of other variables.

True [87]

To do this we need to move 10 to other side. To accomplish this you just need to add 10 to both side since (-10)

so
A+ 10 = c -10 + 10
we get
A+ 10 = c

lets say it wasn't -10 but positive 10.

A = c + 10 then we would subtract 10 from both sides

A -10 = c + 10 - 10
we get
A - 10 = C

5 0

3 years ago

Two sides of a triangle have lengths of 7 ft and 15 fr. Which inequality represents the possible length for the third side, x?

Inessa05 [86]

6 < c < 20,

Of course if you knew the triangle was a right triangle you could use the Pythagorean theorem to directly get the size of the third side.

3 0

3 years ago

a collection of coins consist of nickels, dimes, and quarters. there are 3 fewer quarters than nickels and six more dimes than q

ZanzabumX [31]

There are 12 Nickels, 9 Quarters, and 15 Dimes.

7 0

3 years ago

The third-degree Taylor polynomial about x = 0 of In(1 - x) is

gizmo_the_mogwai [7]

Answer:

$\displaystyle P_3(x) = -x - \frac{x^2}{2} - \frac{x^3}{3}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Functions
Function Notation

Calculus

Derivatives

Derivative Notation

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

MacLaurin/Taylor Polynomials

Approximating Transcendental and Elementary functions
MacLaurin Polynomial: $\displaystyle P_n(x) = \frac{f(0)}{0!} + \frac{f'(0)}{1!}x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3 + ... + \frac{f^{(n)}(0)}{n!}x^n$
Taylor Polynomial: $\displaystyle P_n(x) = \frac{f(c)}{0!} + \frac{f'(c)}{1!}(x - c) + \frac{f''(c)}{2!}(x - c)^2 + \frac{f'''(c)}{3!}(x - c)^3 + ... + \frac{f^{(n)}(c)}{n!}(x - c)^n$

Step-by-step explanation:

*Note: I will not be showing the work for derivatives as it is relatively straightforward. If you request for me to show that portion, please leave a comment so I can add it. I will also not show work for elementary calculations.

Step 1: Define

Identify

f(x) = ln(1 - x)

Center: x = 0

n = 3

Step 2: Differentiate

[Function] 1st Derivative: $\displaystyle f'(x) = \frac{1}{x - 1}$
[Function] 2nd Derivative: $\displaystyle f''(x) = \frac{-1}{(x - 1)^2}$
[Function] 3rd Derivative: $\displaystyle f'''(x) = \frac{2}{(x - 1)^3}$

Step 3: Evaluate Functions

Substitute in center x [Function]: $\displaystyle f(0) = ln(1 - 0)$
Simplify: $\displaystyle f(0) = 0$
Substitute in center x [1st Derivative]: $\displaystyle f'(0) = \frac{1}{0 - 1}$
Simplify: $\displaystyle f'(0) = -1$
Substitute in center x [2nd Derivative]: $\displaystyle f''(0) = \frac{-1}{(0 - 1)^2}$
Simplify: $\displaystyle f''(0) = -1$
Substitute in center x [3rd Derivative]: $\displaystyle f'''(0) = \frac{2}{(0 - 1)^3}$
Simplify: $\displaystyle f'''(0) = -2$

Step 4: Write Taylor Polynomial

Substitute in derivative function values [MacLaurin Polynomial]: $\displaystyle P_3(x) = \frac{0}{0!} + \frac{-1}{1!}x + \frac{-1}{2!}x^2 + \frac{-2}{3!}x^3$
Simplify: $\displaystyle P_3(x) = -x - \frac{x^2}{2} - \frac{x^3}{3}$

Topic: AP Calculus BC (Calculus I/II)

Unit: Taylor Polynomials and Approximations

Book: College Calculus 10e

5 0

3 years ago