Answer this question please ASAP!

Im very confused on this please help me:)

drek231 [11]

The constant rate of change is how much y increases every time x increases by 1. We might be confused because in this table, we see a number of points, but we don't see any consecutive x-values, so it might seem difficult. But no worries!

All you have to do is calculate using the formula, Δy divided by Δx. What does Δy divided by Δx mean?

All we have to do is look at two points. Let's take, for example, (-2, -10) and (2, -8).

-2 and 2 are the x-values of the points and -10 and -8 are the y-values of the points as coordinates are in the format of (x, y).

All we have to do is minus the y-coordinates and then proceed the minus the x-coordinates. The order does not matter, as in you can do either of these ways:

[(-10) - (-8)] ÷ [(-2) - (2)] = -2 / -4 = 1/2

or

[(-8) - (-10)] ÷ [(2) - (-2)] = 2 / 4 = 1/2

So the constant rate of change or the answer is 1/2.

4 0

3 years ago

Read 2 more answers

What does ratio mean

ch4aika [34]

Answer:

A ratio is comparing things. so the ratio of boys to girls. If there was 5 boys and 6 girls that ratio of boys to girls would be

5:6

8 0

3 years ago

How do you solve for x? -12+7=-5(x+2)

dusya [7]

-5= -5x-10

Plus 10 from both sides

5=-5x
X = -1

7 0

3 years ago

Read 2 more answers

Suppose Salma places $5500 in an account that pays 2% interest compounded each year. Assume that no withdrawals are made from th

e-lub [12.9K]

Answer:

Part a) $\$5,610$

part b) $\$5,722.20$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part a) Find the final investment year one

in this problem we have

$t=1\ year\\ P=\$5,500\\ r=2\%=2/100=0.02\\n=1$

substitute in the formula above

$A=5,500(1+\frac{0.02}{1})^{1*1}$

$A=5,500(1.02)^{1}$

$A=\$5,610$

Part b) Find the final investment year 2

in this problem we have

$t=2\ years\\ P=\$5,500\\ r=2\%=2/100=0.02\\n=1$

substitute in the formula above

$A=5,500(1+\frac{0.02}{1})^{1*2}$

$A=5,500(1.02)^{2}$

$A=\$5,722.20$

7 0

3 years ago

The following scatterplot shows the percentage of the vote a candidate received in the 2016 senatorial elections

neonofarm [45]

The critical values corresponding to a 0.01 significance level used to test the null hypothesis of ρs = 0 is (a) -0.881 and 0.881

<h3>How to determine the critical values corresponding to a 0.01 significance level?</h3>

The scatter plot of the election is added as an attachment

From the scatter plot, we have the following highlights

Number of paired observations, n = 8
Significance level = 0.01

Start by calculating the degrees of freedom (df) using

df =n - 2

Substitute the known values in the above equation

df = 8 - 2

Evaluate the difference

df = 6

Using the critical value table;

At a degree of freedom of 6 and significance level of 0.01, the critical value is

z = 0.834

From the list of given options, 0.834 is between -0.881 and 0.881

Hence, the critical values corresponding to a 0.01 significance level used to test the null hypothesis of ρs = 0 is (a) -0.881 and 0.881