All categories

4 years ago

A soccer team has a 4.5- gallon cooler of water during games. How many 4- ounce cups can the team drink per game

Mathematics

1 answer:

Flura [38]4 years ago

8 0

576 ounces/4 ounces = 144 cups they can drink

You might be interested in

18. Solve the equation. m- 10/3 - 5m-9/7 = 1

JulijaS [17]

The answer is m = -59/42

Step by step explanation is in the image below.

4 0

3 years ago

I REALLY NEED THIS SOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOPER BADLY

VLD [36.1K]

Answer:

8.4 * 10^6

Step-by-step explanation:

8.4 * 10^6

1 million = 1 * 10^6

8 million 4 hundred thousand is 8.4 * 10^4 because this number is 8.4 times bigger than a million.

6 0

3 years ago

Solve by completing the square with working out -6x-x^2-8

Goryan [66]

-6x-x^2-8 = -(x+2) x (x+4)

(This is if you are factoring the expression)

7 0

3 years ago

Pira drives 825 miles to California. The trip takes him 17 hours. He uses 38 gallons of gas on the trip, which costs him $125. F

Lunna [17]

Speed = Distance / time:

Speed = 825 miles / 17 hours

Speed = 48.529 miles per hour. (Round the answer as needed).

Gas mileage = miles traveled / gallons used

Gas mileage = 825 miles / 38 gallons = 21.71 miles per gallon (Round answer as needed).

Unit rate of gas = Total money spend / gallons bought:

Unit rate of gas = $125 / 38 gallons = $3.289 per gallon.

5 0

3 years ago

Read 2 more answers

A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha

s2008m [1.1K]

Answer:

Part 1) The lateral area of the cone is $LA=2\pi\ cm^{2}$

Part 2) The lateral surface area of the cylinder is $LA=36\pi\ cm^{2}$

Part 3) The surface area of the crayon is $SA=41.50\pi\ cm^{2}$

Step-by-step explanation:

Part 1) Find the lateral area of the cone

The lateral area of the cone is equal to

$LA=\pi rl$

we have

$r=1\ cm$

$l=2\ cm$

substitute

$LA=\pi (1)(2)$

$LA=2\pi\ cm^{2}$

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

$LA=2\pi rh$

we have

$r=1.5\ cm$

$h=12\ cm$

substitute

$LA=2\pi (1.5)(12)$

$LA=36\pi\ cm^{2}$

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

Find the area of the bottom base of the crayon

$A=\pi[r2^{2}-r1^{2}]$

where

r2 is the radius of the cylinder

r1 is the radius of the cone

substitute

$A=\pi[1.5^{2}-1^{2}]$

$A=1.25\pi\ cm^{2}$

Find the area of the top base of the cylinder

$A=\pi(1.5)^{2}=2.25\pi\ cm^{2}$

Find the surface area

$SA=2\pi+36\pi+2.25\pi+1.25\pi=41.50\pi\ cm^{2}$

8 0

3 years ago

Read 2 more answers