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2 years ago

Jimmy is putting up a fence around his rectangular garden. One side of the garden is 20 feet long, and b represents the width

Mathematics

1 answer:

kondor19780726 [428]2 years ago

3 0

Answer:

(40+2b)cm

Step-by-step explanation:

Complete question

Jimmy is putting up a fence around his rectangular garden. One side of the garden is 20 feet long, and b represents the width, How much fencing material will he need.

To get the amount of fencing material needed, we will find the perimeter of the fence

perimeter of the fence = 2(L+W)

L is the length

W is the width

Given

Length = 20feet

Width = b feet

perimeter of the fence = 2(20+b)

perimeter of the fence = 2(20) + 2b

perimeter of the fence = 40+2b cm

Hence the amount of material needed will be (40+2b)cm

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1: 8 faces and 9 with the base 9 vertices and 16 edges

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3 years ago

Find the slope of the line that passes through (8, 4) and (5, 2).

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3 years ago

Let f(x) represent a function.

STatiana [176]

Answer:

For $f(x+\frac{5}{4})$ , $f(x)$ is translated $\frac{5}{4}$ units left.

For $f(x)-\frac{5}{4}$ , $f(x)$ is translated $\frac{5}{4}$ units down.

Step-by-step explanation:

The transformation of $f(x)\rightarrow f(x+C)$ means that the graph shift to left by C units if C is positive number and shifts to right by C units if C is a negative number.

The transformation of $f(x)\rightarrow f(x)+C$ means that the graph shifts up by C units if C is positive number and shifts down by C units if C is a negative number.

Here, in the transformation of $f(x)\rightarrow f(x+\frac{5}{4}),C = \frac{5}{4}>0$ , so, the function translates left by $\frac{5}{4}$ units.

Similarly, in the transformation of $f(x)\rightarrow f(x)-\frac{5}{4},C = -\frac{5}{4}$ , so, the function translates down by $\frac{5}{4}$ units.

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3 years ago

Two times the sum of a number and 22 is atleast -28<br><br> please hurry

Marta_Voda [28]

Answer:

-6

Step-by-step explanation:

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2 years ago

The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as

bija089 [108]

Answer:

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(score of the 36 golfers was between 70 and 71)

$\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}$

$P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%$

$P(70 \leq x \leq 71) = 47.7\%$

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

8 0

3 years ago