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3 years ago

HI CAN SOMEONE PLS HELP ITS DUE IN 5 min pls help !!!

Mathematics

1 answer:

notsponge [240]3 years ago

3 0

The question wants to determine BOTH at an amount of time.

Green lawn: 28x2=46+42=98 | 28x3=84+42=126

These are incorrect | These are correct

Yard guard: 34x2=68+ 24=92 | 34x3=102+24=126

So then 3 months and 126 dollars

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Silvio works at a car wash. He earns $50 per day and $12 per car washed. Silvio wants to earn at least $158 in 1 day.

iren [92.7K]

Answer:

50+12x≥158

Step-by-step explanation:

starting with $50, adding $12 for every car washed (x), must be at least, but can be greater than, $158.

5 0

4 years ago

Exercise 5.2. Suppose that X has moment generating function

soldi70 [24.7K]

Answer:

a) Mean, E(X) = - 0.5

Variance = = 9.25

b) $M_{X}(t)=E(e^{tX})$

⇒ $=\sum e^{tx}p(x)$

⇒ $=\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}$

Step-by-step explanation:

Given:

moment generating function of X as:

MX(t) = $\frac{1}{2} + \frac{1}{3}e^{-4t} + \frac{1}{6} e^{5t}$

a) Now

Mean, E(X) = $M_{X}'(t=0)$

Thus,

$M_{X}'(t)=\frac{1}{3}(-4)e^{-4t}+\frac{1}{6}(5)e^{5t}$

$M_{X}'(t)=\frac{-4}{3}e^{-4t}+\frac{5}{6}e^{5t}$

also,

$E(X^{2})=M_{X}''(t=0)$

Thus,

$M_{X}''(t)=\frac{-4}{3}(-4)e^{-4t}+\frac{5}{6}(5)e^{5t}$

$M_{X}''(t)=\frac{16}{3}e^{-4t}+\frac{25}{6}e^{5t}$

Therefore,

Mean, E(X) = $M_{X}'(t=0)=\frac{-4}{3}e^{-4(0)}+\frac{5}{6}e^{5(0)}$

Mean, E(X) = - 0.5

and

$E(X^{2})=M_{X}''(t=0)=\frac{16}{3}e^{-4(0)}+\frac{25}{6}e^{5(0)}$

$E(X^{2})$ = 9.5

also,

Variance(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

b) Now,

Let f(x) be the PMF of X

Thus,

$M_{X}(t)=E(e^{tX})$

⇒ $=\sum e^{tx}p(x)$

⇒ $=\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}$

Therefore,

at x = 0, P(x) = $\frac{1}{2}$

at x= - 4 ,P(x) = $\frac{1}{3}$

at x = 5, P(x) = $\frac{1}{6}$

Thus,

E(X) = $\sum xP(x)=0(\frac{1}{2})+(-4)(\frac{1}{3})+5(\frac{1}{6})$

E(X) = - 0.5

also, $E(X^{2})=\sum x^{2}P(x)=0^{2}(\frac{1}{2})+(-4)^{2}(\frac{1}{3})+5^{2}(\frac{1}{6})$

$E(X^{2})$ = 9.5

Hence,

Var(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

4 0

4 years ago

The length and breadth of a rectangles are in the ratio 8:5. If its perimeter is 104cm, find the length of the rectangle

valkas [14]

20.8 cm

so sorry if incorrect :(

7 0

3 years ago

Read 2 more answers

Factor the expression 3x^2 - 15x<br> i will mark brainliest

tensa zangetsu [6.8K]

Step-by-step explanation:

The table of three and x is common

3x ( x + 5)

Is the answer

7 0

3 years ago

Read 2 more answers

Use the given data to find the 95% confidence interval estimate of the population mean μ. Assume that the population has a norma

loris [4]

Answer: For 95% Confidence Interval:

Upper Limit = 110.2

Lower Limit = 97.8

95% Confidence Interval = [97.8, 110.2]

Step-by-step explanation:

Given that,

Mean(M) = 104

Standard Deviation(SD) = 10

Sample Size(n) = 10

Formula for calculating 95% Confidence Interval are as follows:

Standard error(SE) = $\frac{SD}{\sqrt{n} }$

= $\frac{10}{\sqrt{10} }$

= 3.164

⇒ M ± $Z_{0.95}$ × SE

= 104 ± (1.96)(3.164)

= 104 ± 6.20

∴ Upper Limit = 104 + 6.20 = 110.2

Lower Limit = 104 - 6.20 = 97.8

So,

95% Confidence Interval = [97.8, 110.2]

6 0

3 years ago