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marta [7]
2 years ago
13

If a silver alloy that costs $4.50 an ounce is

Mathematics
2 answers:
Norma-Jean [14]2 years ago
7 0

Answer:

4 ounces

10 ounces of $8 + 4 ounces of $4.5 =$98 ÷ by 14 = $7

Nitella [24]2 years ago
5 0

6.5X + 9(30) = 8(30+X)6.5X +270 = 240 + 8X270-240 = 8X-6.5X1.5X = 30X = 30/1.5 =20 ounces of $6.50 alloy9 is within 1 of 86.5 is within 1.5 of 81.5 is 3/2 of 130 is 3/2 of 20You know you need more of $9 alloy since it's closer to $8You need exactly 3/2 or 1.5 times more of the $9 alloy30 is 1.5 times 20

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Which equation demonstrates the additive identity property?
Bezzdna [24]

Answer:

Step-by-step explanation:

Solve for o in the equation (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 41o(7 + 4)(1) = 7 + 41o(7 + 41) + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 41o(7 + 4): Distribute the 41o to each term in (7+4)

41o * 7 = (41 * 7)o = 287o 41o * 4 = (41 * 4)o = 164o

Our Total expanded term is 287o + 164o

Simplify 41o(7 + 41): Distribute the 41o to each term in (7+41)

41o * 7 = (41 * 7)o = 287o 41o * 41 = (41 * 41)o = 1681o

Our Total expanded term is 287o + 1681o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o(1) = 7 + 287o + 1681o + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 164o(1): Distribute the 164o to each term in (1)

164o * 1 = (164 * 1)o = 164o Our Total expanded term is 164o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o = 7 + 287o + 1681o + ( - 7 - 41) = 0

Step 1: Group variables: We need to group our variables (7 and 14©(7. To do that, we subtract 14©(7 from both sides (7 - 14©(7 = 14©(7 - 14©(7

Step 2: Cancel 14©(7 on the right side: 0o = 0 Step 3: Divide each side of the equation by 0

0o 0 = 0 0 o =

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3 years ago
If 50 × a = 50, then what is the value of 50 − a ?
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Answer: 50 - a = 49

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