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3 years ago

10

Are my angles correct?

1 answer:

Licemer1 [7]3 years ago

6 0

Answer:

Yes. You are correct.

Step-by-step explanation:

Tan(U) = opposite / adjactent

Tan(U) = 7*√3 / 7

Tan(U) = √3

Just off the top of my head, they look right.

U = Tan-1 (√3)

U = 60

Therefore tan(W) = 90 - 60 = 30

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Rick invests $7,174 in an account that earns an annual interest rate of 3%. What will be the balance of the account in 18 years

vfiekz [6]

Answer:

A

Step-by-step explanation:

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3 years ago

The unbalanced wheel has a mass of 15 kg and rolls without slipping on the flat horizontal surface. The wheel has a radius of gy

miv72 [106K]

Answer:

a) $a_w=4.331m/s^2$

b) $F=53.7N$

c) $\mu=96.5N$

Step-by-step explanation:

From the question we are told that

mass of unbalanced wheel $M=15kg$

Radius of gyration $G=64m$

Mass center $M_c =40mm=$ $4*10^{-2} m$

Angular velocity $\omega=4rads/s$

a)

Generally the equation for moment at point A is mathematically given as

$\sum M_a=I \alpha+\sum M \=ad$

Where $a_w=wheel\ accelaration$

$15*9.81*(0.04)=0.06144*\frac{a_w}{0.1}+15(0.04)(0.04)\frac{a_w}{0.1}+(15a_w-15(0.04)(4^2)0.1)$

$5,87=(a_w*0.8544+15a_0-0.96)$

$a_w=4.331m/s^2$

b)

Generally the equation for equilibrium of system on the horizontal axis is mathematically given as

$\sum f_x=ma_w$

$F=ma_w-m \=r w^2$

$F=(25*4.221)-(15*0.04*4^2)$

$F=63.3-9.6$

$F=53.7N$

c)

Generally the equation for equilibrium of system on the vertical axis is mathematically given as

$\sum f_y=ma_w$

Where

$F=\mu-mg+m \=r \alpha$

$\alpha=\frac{a_0}{0.1}$

$\mu-mg+m \=r \alpha=0$

$\mu-15*9.81+15*0.04*\frac{4.221}{0.1}$

$\mu-96.5N=0$

$\mu=96.5$

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3 years ago

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Aleonysh [2.5K]

Answer:

y=5/2 x

Step-by-step explanation:

The standard form of a linear equation is Ax +By=C

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3 years ago

What is the actual distance between these streets?

scoundrel [369]

It's D 4 3/8 miles

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The answer of it is:
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3 years ago

Read 2 more answers