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Mashcka [7]
3 years ago
12

Ethical Behavior Worksheet Situation 1. You are taking a very difficult chemistry course, which you must pass to maintain your s

cholarship and to avoid damaging your application for graduate school. Chemistry is not your strong suit, and, because of a just-below-failing average in the course, you will have to receive a grade of 90 or better on the final exam, which is two days away. A janitor, who is aware of your plight, informs you that he found the master for the chemistry final in a trash barrel and has saved it. He will make it available to you for a price, which is high but which you could afford. What would you do?
Chemistry
1 answer:
krok68 [10]3 years ago
4 0

Answer:

I would not accept it.

Explanation:

Although it is tempting to accept the janitor's offer and save the scholarship, which is not easy to get, I would not accept his offer, as I do not believe in victories based on dishonesty and would be heavy on conscience if I did the opposite. Obviously, I would not like to lose my scholarship and for that reason, I would look for other ways that would be honest and help me improve my grade. If I could not improve and lose the scholarship, I would be extremely sad, but I would be at peace with my conscience.

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How many Oxygen atoms in: 5H2SO3
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20

Explanation: I think

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One of the intermediates in the synthesis of glycine from ammonia, carbon dioxide, and methane is aminoacetonitrile, C2H4N2. The
sleet_krkn [62]

Answer:

Mass of C₂H₄N₂ produced = 3.64 g

Explanation:

The balanced chemical equation for the reaction is given below:

3CH₄ (g) + 5CO₂ (g) + 8NH₃ (g) → 4C₂H₄N₂ (g) + 10H₂O (g)

From the equation, 3 moles of CH₄ reacts with 5 moles of CO₂ and 8 moles of NH₃ to produce 4 moles of C₂H₄N₂ and 10 moles of H₂O

Molar masses of the compounds are given below below:

CH₄ = 16 g/mol; CO₂ = 44 g/mol; NH3 = 17 g/mol; C₂H₄N₂ = 56 g/mol; H₂O g/mol

Comparing the mole ratios of the reacting masses;

CH₄ = 1.65/16 = 0.103

CO₂ = 13.5/44 = 0.307

NH₃ = 2.21/17 = 0.130

converting to whole number ratios by dividing with the smallest ratio

CH₄ = 0.103/0.103 = 1

CO₂ = 0.307/0.103 = 3

NH₃ = 0.130/0.103 = 1.3

Multiplying through with 5

CH₄ = 1 × 5 = 5

CO₂ = 3 × 5 = 15

NH₃ = 1.3 × 5 = 6.5

Therefore, the limiting reactant is NH₃

8 × 17 g (136 g) of NH₃ reacts to produce 4 × 56 g (224 g) of C₂H₄N₂

Therefore, 2.21 g of NH₃ will produce (2.21 × 224)/136 g of C₂H₄N₂ = 3.64 g of C₂H₄N₂

Mass of C₂H₄N₂ produced = 3.64 g

7 0
3 years ago
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If a 12-volt battery produces a current of 20 amps, what is the resistance?
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Answer:

0.6 Ω

Explanation:

From the question given above, the following data were obtained:

Voltage (V) = 12 V

Current (I) = 20 A

Resistance (R) =?

From Ohm's law,

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Where:

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I => is the current

R => R is the resistance

With the above formula, we can obtain the resistance as follow:

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Resistance (R) =?

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12 = 20 × R

Divide both side by 20

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R = 0.6 Ω

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