of the compound is found to be 5.04 ×
.
Solubility :Solubility can be define as the amount of a substance that dissolves or mixes in a given amount of solvent at specific conditions.
Solubility equilibrium
Ksp = ![[A^{+} ]^{a}](https://tex.z-dn.net/?f=%5BA%5E%7B%2B%7D%20%5D%5E%7Ba%7D)
![[B^{-} ]^{b}](https://tex.z-dn.net/?f=%5BB%5E%7B-%7D%20%5D%5E%7Bb%7D)
Ksp = solubility product constant
A+ = cation in an aquious solution
B- = anion in an aqueous solution
a, b = relative concentrations of a and b
Given,
Solubility = s = 3.60 × 
g/L
molar mass = 288 g/ mol
∴ s= 3.60 × g/L ÷ 288 g/ mol = 1.25 ×
mol/ L
Reaction:
MX3 ⇄ M + 3X
s 3s
=[ 
] [ 
![]^{3}](https://tex.z-dn.net/?f=%5D%5E%7B3%7D)
= solubility product
∴ =![[s]^{} [3s]^{3}](https://tex.z-dn.net/?f=%5Bs%5D%5E%7B%7D%20%5B3s%5D%5E%7B3%7D)
∴ = 3 
∴ = 3 × (3.60 × 
∴ = 503.8848 ×
= 5.04 ×
Learn more about solubility here .....
brainly.com/question/23946616
#SPJ1
Answer:The kinetic-molecular theory of gases assumes that ideal gas molecules (1) are constantly moving; (2) have negligible volume; (3) have negligible intermolecular forces; (4) undergo perfectly elastic collisions; and (5) have an average kinetic energy proportional to the ideal gas's absolute temperature.
Explanation:
Another advantage of advantage of using a microspectrophotometer to analyze fibers asides not causing damage to the sample is that the sample can be quite small.
<h3>What is a microspectrophotometer?</h3>
Microspectrophotometry is a biological technique used to measure the absorption or transmission spectrum of a solid or liquid material in either transmitted or reflected light.
Microspectrophotometry can also measure the emission of light by a sample, which is usually small as the micro implies.
One advantage of microspectrophotometry is that the sample does not get damaged. However,
However, another advantage of advantage of using a microspectrophotometer to analyze fibers asides not causing damage to the sample is that the sample can be quite small.
Learn more about microspectrophotometry at: brainly.com/question/5832827
C. that is the answer to the question
Answer:
C2 2+ stable and should exist
Be2 2+ stable and should exit
Li2 stable and should exit
Li2 2- unstable and doesn't exist
Explanation:
The first step in predicting the stability of a specie is knowing its molecular orbital configuration and bond order. If the Specie has a bond order of one or more, it is expected to exist in a stable form. The image attached shows the bond order and molecular orbital configuration of all the species mentioned in the question. This will aid you in understanding the stability of each specie.
