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Brrunno [24]
4 years ago
15

Write equations for the reaction of 1 mol of Barium Hydroxide with 2 Moles of hydrochloric acid

Chemistry
1 answer:
gtnhenbr [62]4 years ago
5 0

Answer:

Ba(OH)₂(aq) + 2HCl(aq) → BaCl₂(aq) + 2H₂O(l).

Explanation:

1 mol of Barium Hydroxide with 2 moles of hydrochloric acid  to produce 1 mol of barium chloride and 2 moles of water according to the equation:

<em>Ba(OH)₂(aq) + 2HCl(aq) → BaCl₂(aq) + 2H₂O(l). </em>

<em></em>

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Caffeine is a compound found in some natural coffees and teas and in some colas. a. Determine the empirical formula for caffeine
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Answer: The molecular formula will be C_8N_4H_{10}O_2

Explanation:

Mass of C= 49.47 g

Mass of N = 28.85 g

Mass of O = 16.48 g

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Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{49.47g}{12g/mole}=4.12moles

Moles of N =\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{28.85g}{14g/mole}=2.06moles

Moles of O =\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{16.48g}{16g/mole}=1.03moles

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{5.20g}{1g/mole}=5.20moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{4.12}{1.03}=4

For N = \frac{2.06}{1.03}=2

For O =\frac{1.03}{1.03}=1

For H = \frac{5.20}{1.03}=5

The ratio of C : N: O: H = 4: 2: 1: 5

Hence the empirical formula is C_4N_2OH_5

The empirical weight of C_4N_2OH_5 = 4(12)+2(14)+1(16)+5(1)= 97 g.

The molecular weight = 194.19 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{194.19}{97}=2

The molecular formula will be = 2\times C_4N_2H_5O=C_8N_4H_{10}O_2

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