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3 years ago

8

Yvonne wants to cover the back of her smartphone with a decorative pattern. If the phone's length is 1/2 foot and width is 1/6 f

oot, what is the area that the decorative pattern will cover?

1 answer:

allochka39001 [22]3 years ago

4 0

Answer:

1/12 square foot

Step-by-step explanation:

Area of the pattern = LEngth * Width

Given the following

Length = 1/2 foot

Width = 1/6 foot

Area of the pattern = 1/2 * 1/6

Area of the pattern =1/12 square foot

Hence the area that the decorative pattern will cover will be 1/12 square foot

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Which equation results from adding the equations in this system?

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Answer: 3x=3

Step-by-step explanation: Let's divide this into parts--

1. Adding the x variables: -2x+5x or 5x-2x = 3x.

2. Adding the y variables: y-y or -y+y = 0. (The negative and the positive y cancel each other out.)

3. Adding the numbers: 8-5 or -5+8 = 3.

Now just put it back into an equation: 3x + 0 = 3.

We don't need to add the 0, so the equation changes into 3x = 3.

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Step-by-step explanation:

(f+g)(x) means f(x)+g(x). Since we are given f(x) and g(x), we cna add them together.

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3 years ago

The estimated probability of a bowler getting a strike during a particular frame is 63%. If several simulations of the bowler bo

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Answer: Our required probability is 39.69%.

Step-by-step explanation:

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3 years ago

I need help. (image below)

vovangra [49]

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Step-by-step explanation:

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3 years ago

You have been asked to design a can shaped like right circular cylinder that can hold a volume of 432π-cm3. What dimensions of t

rosijanka [135]

Answer:

$Height = 12cm$

$Radius = 6cm$

Step-by-step explanation:

Given

Represent volume with v, height with h and radius with r

$V = 432\pi$

Required

Determine the values of h and r that uses the least amount of material

Volume is calculated as:

$V = \pi r^2h\\$

Substitute 432π for V

$432\pi = \pi r^2h$

Divide through by π

$432 = r^2h$

Make h the subject:

$h = \frac{432}{r^2}$

Surface Area (A) of a cylinder is calculated as thus:

$A=2\pi rh+2\pi r^2$

Substitute $\frac{432}{r^2}$ for h in $A=2\pi rh+2\pi r^2$

$A=2\pi r(\frac{432}{r^2})+2\pi r^2$

$A=2\pi (\frac{432}{r})+2\pi r^2$

Factorize:

$A=2\pi (\frac{432}{r} + r^2)$

To minimize, we have to differentiate both sides and set $A' = 0$

$A'=2\pi (-\frac{432}{r^2} + 2r)$

Set $A' = 0$

$0=2\pi (-\frac{432}{r^2} + 2r)$

Divide through by $2\pi$

$0= -\frac{432}{r^2} + 2r$

$\frac{432}{r^2} = 2r$

Cross Multiply

$2r * r^2 = 432$

$2r^3 = 432$

Divide through by 2

$r^3 = 216$

Take cube roots of both sides

$r = \sqrt[3]{216}$

$r = 6$

Recall that:

$h = \frac{432}{r^2}$

$h = \frac{432}{6^2}$

$h = \frac{432}{36}$

$h = 12$

Hence, the dimension that requires the least amount of material is when

$Height = 12cm$

$Radius = 6cm$

3 0

3 years ago