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sergey [27]
3 years ago
14

What is the answer to the photo below? (Supposed to be a fraction)

Mathematics
2 answers:
ankoles [38]3 years ago
7 0
-3x=-7
This x=7/3 hope this helps :)
rosijanka [135]3 years ago
4 0
So you start with -3x=-7 because you add like terms. Then you divide both sides by -3 and you get X=2.33
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Use a real number to represent the situation.<br> The temperature falls 14°F.
iVinArrow [24]

Answer:

-14°F

Step-by-step explanation:

Hey there!

7 0
3 years ago
Ellis is painting wooden fenceposts before putting them in his yard. They are each 6 feet tall and have a diameter of 1 foot. Th
katen-ka-za [31]

Answer:

244.92 ft^2

Step-by-step explanation:

Find out the surface area of 1 fence post.

It has 2 circular parts (a bottom and a top)

r = d / 2

r = 1 / 2

r = 0.5 feet.

Area = 3.14 * 0.5^2

area = 3.14 * 0.25

Area = 0.785

Each post has 2 such shapes. 2 * 0.785 = 1.57

There are 12 posts with areas of 1.57 on the bottom and top  = 18.84 ft^2

Find the area of the long part of the post

h = 6 feet

circumference = 2* pi * r

circumference = 2* 3.14 * .5

circumference = 3.14

The height is 6 feet.

The area of the body of the pole 6 *circumference = 6 * 3.14 = 18.84 ft^2

There are 12 poles.

Total area = 12 *18.84 ft^2 =  226.08

Total area = 12 bodies + 24 ends

Total area = 226.08 + 18.84

Total area = 244.92

4 0
3 years ago
How much of a 14% solution of iodine should be added to 89 ounces of a 47% iodine solution to get a 29% solution
Andrews [41]
We have 89 ounces of 47% iodine.
We will add "x" ounces of 14% iodine to get a 29% iodine solution.
89 * .47 + .14x = .29 * (89 + x)
41.83 + .14x = 25.81 + .29x
16.02 = .15x
x = 106.80
So, we must add 106.80 ounces of 14% iodine to get a 29% iodine solution.
(for a total of 195.80 ounces)

Source:
http://www.1728.org/mixture.htm


3 0
3 years ago
You are given 1000 one dollar bills and 10 envelopes. Put the bills into the envelopes in such a way that someone can ask you fo
taurus [48]

Answer:

We can do it with envelopes with amounts $1,$2,$4,$8,$16,$32,$64,$128,$256 and $489

Step-by-step explanation:

  • Observe that, in binary system, 1023=1111111111. That is, with 10 digits we can express up to number 1023.

This give us the idea to put in each envelope an amount of money equal to the positional value of each digit in the representation of 1023. That is, we will put the bills in envelopes with amounts of money equal to $1,$2,$4,$8,$16,$32,$64,$128,$256 and $512.

However, a little modification must be done, since we do not have $1023, only $1,000. To solve this, the last envelope should have $489 instead of 512.

Observe that:

  1. 1+2+4+8+16+32+64+128+256+489=1000
  2. Since each one of the first 9 envelopes represents a position in a binary system, we can represent every natural number from zero up to 511.
  3. If we want to give an amount "x" which is greater than $511, we can use our $489 envelope. Then we would just need to combine the other 9 to obtain x-489 dollars. Since x-489\leq511, by 2) we know that this would be possible.

4 0
3 years ago
Help please is for now
zmey [24]
Answer: 5

Steps:
5x - 2y = 30
5(8) - 2y = 30
40 - 2y = 30
-2y = 30 - 40
-2y = -10
y = -10/-2
y = 5

I would appreciate the brainliest if this answer was correct and the steps were clear and helpful! :)
3 0
3 years ago
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