By completing the square: x²-8x+19 = (x-4)²-16+19 = (x-4)²+3 so minimum point = (4,3)
By calculus: f'(x) = 2x-8. (minimum point occurs when f'(x)=0 therefore)
2x-8 = 0 means x=4 and the corresponding y value is 3.
The minimum value of this function (y) is 3 and this occurs when x = 4.
Answer: I'm not sure if this is right or not but I got U = 4
Step-by-step explanation: -8(2v-2)=-4(7+5u. So first I distributed and got -16v -16 = 28 + 20u. And then I added 16u with 20u I added because you change the sign like if it's a negative you make it a positive so once you do 20u+16v you should get 36 and then on the other side it should be -16+16 which equals -16u from when you distributed so now you should have -16u=28+36 so now you would add 28 the 36 since they both are positives and have no variables which you should get 64 and then on the left you should have 16u. So it looks like -16u=64. And then now you would divide -16u on both sides and the side with the variable put it or v whatever variable you want to use and then do 64 divided by 16 and you should get 4.
Think of it like a triangle.
The flagpole is vertical and is at 90° to the ground. This makes a right-angle to the ground, which is flat.
Since we have two sides of the triangle already, and they are in a ratio of ?? : 16 : 20 = ?? : 4 : 5, that means that because the triangle is a right-angled triangle, the third and last side must be 3 to complete the ratio! (This is called 'Pythagoras')
Since the other sides were divided by 4 to get the simple ratio, we must multiply 3 to get the actual ratio!
3 × 4 = 12 ft tall flagpole.
Answer:
c is the correct answer mate
Step-by-step explanation:
have a greate day bye
840? Im not sure im sorry