Question

Let an integer be chosen at random from the integers 1 to 30 inclusive. Find the probability that the integer chosen is divisible by 3.

Answer 1

There are 30 total integers. 10 of these will be divisible by 3 (all multiples of 3 between 3 and 30). So the probability of getting an integer evenly divisible by 3 is $\dfrac{10}{30}=\dfrac13$.

Answer 2

Answer:

probability that the integer chosen is divisible by 3 is  $\frac{1}{3}$.

Step-by-step explanation:

Given : An integer be chosen at random from the integers 1 to 30 inclusive.

To find  : Find the probability that the integer chosen is divisible by 3.

Solution : We have integers 1 to 30.

We need to find probability that the integer is divisible by 2.

We know that multiple of 3 is divisible by 3

All multiple of 3 from 1 to 30 ( 3,6,9,12,15,18,21,24,27,30)

Total multiple of 3 from  1 to 30 =  10 .

Probability = $\frac{Favourble\ outcome}{Total\ number\ of\ outcome}$

Probability = $\frac{10}{30}$

Probability =  $\frac{1}{3}$.

Therefore, probability that the integer chosen is divisible by 3 is  $\frac{1}{3}$.