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konstantin123 [22]
3 years ago
5

It is twice as far from (3,0) as it is from the y axis

Mathematics
1 answer:
DIA [1.3K]3 years ago
4 0
(3,6). 3 units from point. 6 units from y axis. 
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I need to figure this out
RUDIKE [14]

Answer:

plug in the missing numbers and you have the answers

Step-by-step explanation:

  1. 6×5=2
  2. 32+4×3=44
  3. 27×3-(16+3×5)=50
  4. 7×5÷3+2=13.6
  5. 2×7-4×3=2
8 0
3 years ago
Solve the following simultaneous equation by using an algebraic method (either substitution or elimination)
Maru [420]

Answer:

( \frac{29}{14}, - \frac{19}{7})

Step-by-step explanation:

given the 2 equations

2x + 3y = - 4 → (1)

4x - y = 11 → (2)

Rearrange (2) expressing y in terms of x, that is

y = 4x - 11 → (3)

Substitute y = 4x - 11 into (1)

2x + 3(4x - 11) = - 4

2x + 12x - 33 = - 4

14x - 33 = - 4 ( add 33 to both sides )

14x = 29 ( divide both sides by 14 )

x = \frac{29}{14}

Substitute this value into (3) for corresponding value of y

y = (4 × \frac{29}{14}) - 11 = \frac{116}{14} - \frac{154}{14} = - \frac{38}{14} = - \frac{19}{7}

solution is ( \frac{29}{14}, - \frac{19}{7})



7 0
4 years ago
Simplify the surd 3√ 20 +√ 45 ​
melisa1 [442]

Answer:

9\sqrt{5}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplify the radicals

\sqrt{20}

= \sqrt{4(5)}

= \sqrt{4} × \sqrt{5}

= 2\sqrt{5}

\sqrt{45}

= \sqrt{9(5)}

= \sqrt{9} × \sqrt{5}

= 3\sqrt{5}

Then

3\sqrt{20} + \sqrt{45}

= 3(2\sqrt{5} ) + 3\sqrt{5}

= 6\sqrt{5} + 3\sqrt{5}

= 9\sqrt{5}

3 0
3 years ago
Read 2 more answers
Derrico is building a holding pen for his dogs. The rectangular holding pen is 14.8 feet wide by 8.9 feet long. About how many f
son4ous [18]

Answer:

11

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the domain and range!!! 10 points!! Help needed
larisa86 [58]

ANSWER

B. Domain is (-∞,∞) and Range is (-∞,∞).

The given function is

f(x) =  \sqrt[3]{x - 6}  + 5

This is function is obtained by shifting the base cubic root function 6 units to the right and 5 units up.

This function is defined for all real values of x.

Therefore the domain is all real numbers.

The range is all real numbers.

The domain for this function becomes the range for the inverse function and the range becomes the domain.

Hence the domain is (-∞,∞) and the range is (-∞,∞).

4 0
4 years ago
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