Answer:
2,655 students
Step-by-step explanation:
The z-score for a 99% confidence interval is z = 2.576
The standard error for a proportion p is:

For a proportion of p =0.20, in order to ensure a standard error of 0.02, the sample size 'n' must be:

Rounding up to the next whole student, the sample size needed is 2,655 students.
The answer is yes
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600,000,000+40,000,000+400,000+9,000+200+10