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3 years ago

HELP ASAP PLEASE & SHOW UR WORK!! THANK YOU <3

Mathematics

1 answer:

olchik [2.2K]3 years ago

4 0

Answer:

x^2 - 5x = 14

x^2 - 5x-14 = 0

Now, we have to find the multiples of -14 and numbers that add/subtract to -5; this helps to find the factors.

-7+2 = -5

-7*2 = -14

Based on the above info, we can find out my factors; they are:-

(x-7)(x+2)

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A claw arcade machine contains stuffed animals and mystery boxes. There are 51 items in the machine. Winning a stuffed animal ha

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Answer: 34 stuffed animals & 17 mystery boxes.

First off, split 51 into three parts, trying to find how much 1/3 is of 51. It equals 17.

The stuffed animals in the machine are “twice as much” of the mystery boxes, so you need to multiply 17 x 2 to find the amount of stuffed animals.

17 x 2 = 34

As for the mystery boxes, you need to multiply it by one.

17 x 1 = 17.

In summary, the answer is 34 stuffed animals and 17 mystery boxes.

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Step-by-step explanation:

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3 years ago

A small town has 2000 families. The average number of children per family is mu = 2.5, with a standard deviation sigma = 1.7. A

Nikitich [7]

Answer:

Let X the random variable that represent the number of children per fammili of a population, and for this case we know the following info:

Where $\mu=2.5$ and $\sigma=1.7$

We select a sample of n =64 >30 and we can apply the central limit theorem. From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And for this case the standard error would be:

$\sigma_{\bar X} = \frac{1.7}{\sqrt{64}}= 0.2125$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable that represent the number of children per fammili of a population, and for this case we know the following info:

Where $\mu=2.5$ and $\sigma=1.7$

We select a sample of n =64 >30 and we can apply the central limit theorem. From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And for this case the standard error would be:

$\sigma_{\bar X} = \frac{1.7}{\sqrt{64}}= 0.2125$

6 0

3 years ago