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Answer:
The value of x that gives the maximum transmission is 1/√e ≅0.607
Step-by-step explanation:
Lets call f the rate function f. Note that f(x) = k * x^2ln(1/x), where k is a positive constant (this is because f is proportional to the other expression). In order to compute the maximum of f in (0,1), we derivate f, using the product rule.
We need to equalize f' to 0
- k*(2x ln(1/x) - x) = 0 -------- We send k dividing to the other side
- 2x ln(1/x) - x = 0 -------- Now we take the x and move it to the other side
- 2x ln(1/x) = x -- Now, we send 2x dividing (note that x>0, so we can divide)
- ln(1/x) = x/2x = 1/2 ------- we send the natural logarithm as exp
- 1/x = e^(1/2)
- x = 1/e^(1/2) = 1/√e ≅ 0.607
Thus, the value of x that gives the maximum transmission is 1/√e.
Answer:
The given question is
<em> Draw two 1 dm squares on a sheet of paper. Draw a diagonal on each one and cut them out.</em>
<em />
So, you need to draw square with sides of 1 dm. However, first, you need to transform from dm to cm.
We know that 1 decimenter (dm) equals 10 centimeters (cm).
That means the square sides are 10 centimerers long. So, you need to draw two squares like the first image attached shows.
Then, to draw their diagonals, you need to draw a line segment from one corner to its opposite corner, you should have an inclined line acroos each square. As the second image attached shows.
There you have it. Two squares of 1 dm side with on diagonal each.
