Answer: The median number of posts made is 8.5
83 boxes are required to carry 800 books.
According to the question:
One Box can hold weight = 30 pounds
We know that , 1 pound= 0.45 kg
hence, 30 pounds = 30 x 0.45 = 13.5kg
hence, one box can carry 13.5 kg of weight.
Now,
Weight of 1 book = 1.4 kg
So, Total Weight of 800 books= 1.4 x 800 kg
And , No. of boxes required to carry 800 books = (1.4 x 800)/13.5 = 82.96
or approximately 83 boxes
Hence, 83 boxes are required to carry 800 books.
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Answer:
{x,y,z} = {-18,4,2}
Step-by-step explanation:
Solve equation [2] for the variable x
x = -10y + 2z + 18
Plug this in for variable x in equation [1]
(-10y+2z+18) + 9y + z = 20
- y + 3z = 2
Plug this in for variable x in equation [3]
3•(-10y+2z+18) + 27y + 2z = 58
- 3y + 8z = 4
Solve equation [1] for the variable y
y = 3z - 2
Plug this in for variable y in equation [3]
- 3•(3z-2) + 8z = 4
- z = -2
Solve equation [3] for the variable z
z = 2
By now we know this much :
x = -10y+2z+18
y = 3z-2
z = 2
Use the z value to solve for y
y = 3(2)-2 = 4
Use the y and z values to solve for x
x = -10(4)+2(2)+18 = -18
Answer:
B
Step-by-step explanation:
Both of them have the same variable and are both raised to the 5th power (Like the example in the last sentence of the text)
Answer:
20x
Step-by-step explanation:
