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Murljashka [212]
3 years ago
14

Help? please? anyone? thank youuu

Mathematics
1 answer:
Montano1993 [528]3 years ago
8 0
The answer is 6. you just count the boxes in between the two points
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Going to college can cost a lot! What are some costs of attending college? Come up with at least 3 different costs.
scoray [572]
Buying books, your dorm and maybe a ride to get to school
6 0
3 years ago
Read 2 more answers
Can anyone explain how to do any of this?
pashok25 [27]

Answer:

qn 10. 15mn² - 23m²n +4m³

Step-by-step explanation:

1. distribute 4m through the parenthesis

8mn² - 12m²n + 4m³ - 2n(5m² - 3nm) + nm(n-m)

2. use the commutative property to reorder the terms

8mn² - 12m²n + 4m³ - 2n(5m² - 3mn) + mn(n - m)

3. distribute -2n through the remaining parenthesis

8mn² - 12m²n + 4m³ -10m²n + 6mn² + mn² - m²n

4. collect like terms

8mn² + 6mn² + mn² - 12m²n - 10m²n - m²n + 4m³

5. complete bodmas

15mn² - 23m²n +4m³

that's is how you do it so the answer is

15mn² -23m²n + 4m³

5 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!
Stells [14]
The answer is A hope this would help you

4 0
3 years ago
Solve for the missing arc measure, angle measure, or variable.
Anastaziya [24]

Answer:

110

Step-by-step explanation:

The answer is 110 degrees. The reason is hard to put into simple language.

If the central angle and the acute angle hitting the circumference share the same end points, then the central angle is double the arc whose vertex is on the circumference.

Read that sentence a couple of times. I don't know how to make it simpler.

The arc angle and the central angle both have B and C as their end points.

The arc angle is on the circumference of the circle. The vertex (A) of BAC is on the circumference. If mine is the only answer, wait a few days before awarding a Brainliest. A thanks will do.

6 0
3 years ago
use synthetic division to determine which of the following are the real zeroes of the function f(x) = 5x^3 + 8x^2 + x - 2
tester [92]
Always try putting x=1 and x=-1 to see if we can find a zero.
If x=1 we get 5+8+1-2 which is not zero.
If we change the signs of the odd powers of x we get -5+8-1-2 which is zero so x=-1 is a zero and x+1 must therefore be a factor. Now we can use synthetic division to find the quadratic:

-1 | 5 8 1 -2
5 -5 -3 2
————
5 3 -2 | 0 = 5x²+3x-2 = (5x-2)(x+1).

Therefore the real zeroes are -1, 2/5, since -1 is a duplicate zero (because the cubic factorises into (5x-2)(x+1)²).
3 0
3 years ago
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