Answer:
Formula for area of triangle:
A = bh x 1/2
Formula for area of parallelogram:
A = bh
Now find the area of the figure above which is a triangle:
3(base) x 8(height) x 1/2 = <em>12</em>
Let's find the area of the parallelogram;
6(height) x 9(base) = <em>54</em>
Add the two areas together:
12 + 54 = 66 cm2
The question is incomplete. Here is the complete question.
Find the measurements (the lenght L and the width W) of an inscribed rectangle under the line y = -
x + 3 with the 1st quadrant of the x & y coordinate system such that the area is maximum. Also, find that maximum area. To get full credit, you must draw the picture of the problem and label the length and the width in terms of x and y.
Answer: L = 1; W = 9/4; A = 2.25;
Step-by-step explanation: The rectangle is under a straight line. Area of a rectangle is given by A = L*W. To determine the maximum area:
A = x.y
A = x(-
)
A = -
To maximize, we have to differentiate the equation:
= 
(-)
= -3x + 3
The critical point is:
= 0
-3x + 3 = 0
x = 1
Substituing:
y = -x + 3
y = -.1 + 3
y = 9/4
So, the measurements are x = L = 1 and y = W = 9/4
The maximum area is:
A = 1 . 9/4
A = 9/4
A = 2.25
Answer:
x + 15
Step-by-step explanation:
Since I don't know what this number is, I'm going to use the variable x to substitute for the value of the unknown number.
So it would just be x + 15 because addition is the operation of adding and the key words are usually more. Since one of the numbers is unknown, we can't get an answer like "100" because x is undefined.
Say x=100, then the number would be written as 115 in it's simplest form but you could also write it as 100+15. So I'm just using substitution.
Answer:
7π
Step-by-step explanation:
SO first find the area of the whole circle
which has a radius of 3
a=πr^2
So 3^2=9
9π
Now the two circles which are the same in area due to having the same radius
so if you plug in the 1 for radius the answer would just be π or 1π
now multiply that by 2 becuase there are 2 identical circles
π*2=2π
Now subtract
9π-2π=7π
Trigonometry can be used to find angles and sides of simple triangles. If an 18-foot ladder touches a building 14 feet up the wall then the angle can be deduced by trigonometry. In this case, the ladder defines the hypotenuse (H) of the triangle and the wall defines the opposite (O) side of the triangle. Therefore we can use the equation theta=sin^-1(O/H) . This yields an angle of 51 degrees.
