The solutions to the equation are
.
You can find the answer to any quadratic by using the quadratic formula. The formula is below.

Then find a (the number attached to x^2), b (the number attached to x) and c (the constant). This will allow you to plug in and solve.




Answer:
a)

b)
The total amount accrued, principal plus interest, from compound interest on an original principal of $ 4,200.00 at a rate of 3.6% per year compounded 12 times per year over 10 years is $5667.28.
Step-by-step explanation:
a. Write the function that represents the value of the account at any time, t.
The function that represents the value of the account at any time, t

where
P represents the principal amount
r represents Annual Rate
n represents the number of compounding periods per unit t, at the end of each period
t represents the time Involve
b) What will the value be after 10 years?
Given
The principal amount P = $4200
Annual Rate r = 3.6% = 3.6/100 = 0.036
Compounded monthly = n = 12
Time Period = t
To Determine:
The total amount A = ?
Using the formula

substituting the values


$
Therefore, the total amount accrued, principal plus interest, from compound interest on an original principal of $ 4,200.00 at a rate of 3.6% per year compounded 12 times per year over 10 years is $5667.28.
A=60
B=52
C=152
I’ve attached my work on how I got these answers
Hope this helps!
Im pretty sure its 15×10 to the -5 and if u wanted expanded its .00015