Answer:
We will split the trapezoid into right angle triangle and rectangle
Traingle with base 3cm and height 10 - 6 = 4cm
Area of traingle
= 
Area of rectangle with sides 6cm and 3cm
=
Therefore, area of the trapezoid
= 
Area of the semi circle with radius 3/2 = 1.5cm
= 
<span>4.8 (x+4)=2.6
Use distributive property
4.8x + 19.2= 2.6
Subtract 19.2 from both sides
4.8x = -16.6
Divide 4.8 on both sides so that the only thing remaining on the left side is the variable x.
Final Answer: x = -3.458</span>
Y=Acos(p)+m, A=amplitude, p=period, m=midline, in this case:
A=1/2, p=360(t/12)=30t, m=(10-9)/2+9=9.5 so
h(t)=(1/2)cos(30t)+9.5
Answer:
y=8/(P+q+4)
Step-by-step explanation:
we can find out that three items have y
so we can get them together Py+qy+4y=8
next(P+q+4)y=8 so y=8/(p+q+4)
The answer is B... T'(0,0), S'(-1,2), R'(1,3), Q'(4,1)
