Answer:
Answer is 0.5
Step-by-step explanation:
The text implies that the number of traffic accidents determines the number of ambulances required on the road. Hence, 1 traffic accident requires 1 ambulance.
The time slot and time of day remain same in both the text and the question.
The average or mean number of accidents is 1.1
QUESTION: What then is the probability that there is need for exactly 2 ambulances on that road and in that time frame?
In other words, what is the probability that there'll be 2 accidents on that road and in that time frame?
Since the mean number of accidents is 1.1, 2 is above the mean.
Probability of 1.1 accidents is 1, since that's the mean (expected value).
Probability of 2 accidents is 1/2 which is = 0.5
9 because the square root of 81 is 9
The number of participants with laptop is 115 and without laptop is 161
<u>Step-by-step explanation:</u>
Total number of participants= 276
Participants with laptop = (5/12) 276
= 115
Participants without laptop= 276 - 115
= 161
F(x)=3x^2 - 2x +1
f(-1)=3(-1)^2-2(-1)+1
f(-1)=3( 1 ) +2+1
f(-1)=3+3
f(-1)=6
Answer: only (x-y=4) and (x+y=4).
Step-by-step explanation:
Notice target point has y=0, so all terms with y are zero. Then all 6 equations reduce to m x = k, for various m and k. So calculate 4×m and compare to k six times.
x - y = 4 4=4 yes
-x - y = 4 -4=4 no
2x - y = 7 8=7 no
x + y = 4 4=4 yes
2x + y = 7 8=7 no
2x + y = -7 8=-7 no.
