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sergeinik [125]
3 years ago
15

4 1\10÷2

frac{1}{10?} \div 2" alt="4 \frac{1}{10?} \div 2" align="absmiddle" class="latex-formula">
plssss help​
Mathematics
2 answers:
lakkis [162]3 years ago
5 0

2.05 I think if the question was just 4 1/10 ÷2

emmainna [20.7K]3 years ago
4 0
<h3><u>Answer</u>:- </h3>

\longrightarrow \sf  2\dfrac{1}{20}

<h3><u>Solution:-</u></h3>

\begin{gathered}\\\implies\quad \sf 4 \frac{1}{10} \div 2 \\\end{gathered}

<u>Converting to mixed fraction-</u>

\begin{gathered}\\\implies\quad \sf  \frac{4\times 10+1}{10} \div 2 \\\end{gathered}

\begin{gathered}\\\implies\quad \sf  \frac{41}{10} \div 2 \\\end{gathered}

\begin{gathered}\\\implies\quad \sf  \frac{41}{10} \div  \frac{2}{1} \\\end{gathered}

\begin{gathered}\\\implies\quad \sf  \frac{41}{10} \times   \frac{1}{2} \\\end{gathered}

\begin{gathered}\\\implies\quad \sf  \frac{41}{20} \\\end{gathered}

<u>Writing final answer again in mixed form </u>

\begin{gathered}\\\implies\quad \sf  2\frac{1}{20} \\\end{gathered}

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Naddika [18.5K]

Answer:

The null hypothesis is H_0: p \leq x, in which x is the proportion tested.

The alternative hypothesis is H_1: p > x

Step-by-step explanation:

A recent article in a university newspaper claimed that the proportion of students who commute more than miles to school is no more than x.

This means that at the null hypothesis, we test if the proportion is of at most x, that is:

H_0: p \leq x

Suppose that we suspect otherwise and carry out a hypothesis test.

The opposite of at most x is more than x, so the alternative hypothesis is:

H_1: p > x

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Luba_88 [7]

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-6w + (-8) + 1 + (-7w)

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-6w + (-7w) = -13w

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However, because adding a negative number is the same as subtracting the number as a positive, you can just make it -13w - 7

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