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sergeinik [125]
2 years ago
15

4 1\10÷2

frac{1}{10?} \div 2" alt="4 \frac{1}{10?} \div 2" align="absmiddle" class="latex-formula">
plssss help​
Mathematics
2 answers:
lakkis [162]2 years ago
5 0

2.05 I think if the question was just 4 1/10 ÷2

emmainna [20.7K]2 years ago
4 0
<h3><u>Answer</u>:- </h3>

\longrightarrow \sf  2\dfrac{1}{20}

<h3><u>Solution:-</u></h3>

\begin{gathered}\\\implies\quad \sf 4 \frac{1}{10} \div 2 \\\end{gathered}

<u>Converting to mixed fraction-</u>

\begin{gathered}\\\implies\quad \sf  \frac{4\times 10+1}{10} \div 2 \\\end{gathered}

\begin{gathered}\\\implies\quad \sf  \frac{41}{10} \div 2 \\\end{gathered}

\begin{gathered}\\\implies\quad \sf  \frac{41}{10} \div  \frac{2}{1} \\\end{gathered}

\begin{gathered}\\\implies\quad \sf  \frac{41}{10} \times   \frac{1}{2} \\\end{gathered}

\begin{gathered}\\\implies\quad \sf  \frac{41}{20} \\\end{gathered}

<u>Writing final answer again in mixed form </u>

\begin{gathered}\\\implies\quad \sf  2\frac{1}{20} \\\end{gathered}

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In a large Introductory Statistics lecture hall, the professor reports that 55% of the students enrolled have never taken a Calc
Anna35 [415]

Answer:

a) There is a 13% probability that a student has taken 2 or more semesters of Calculus.

b) 45% probability that a student has taken some calculus.

c) 87% probability that a student has taken no more than one semester of calculus.

Step-by-step explanation:

We have these following probabilities:

A 55% that a student hast never taken a Calculus course.

A 32% probability that a student has taken one semester of a Calculus course.

A 100-(55+32) = 13% probability that a student has taken 2 or more semesters of Calculus.

a) two or more semesters of Calculus?

There is a 13% probability that a student has taken 2 or more semesters of Calculus.

b) some Calculus?

At least one semester.

So there is a 32+13 = 45% probability that a student has taken some calculus.

c) no more than one semester of Calculus?

At most one semester.

So 55+32 = 87% probability that a student has taken no more than one semester of calculus.

5 0
3 years ago
Read 2 more answers
50 points! Please help fast this is due soon and it confuses me. Will mark brainliest. Random answers will be reported. Please h
Ad libitum [116K]

Answer:(5,3)

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the factored form of the function f(x)=x^3+8x^2+5x−50?
Inga [223]

Answer:

the factors of  f(x)=x^3+8x^2+5x-50 are (x-2)(x+5)(x+5)

Step-by-step explanation:

We need to factorise the function f(x)=x^3+8x^2+5x-50

If a number is a factor of this function than it must be completely divisible by last co-efficient. Our last co-efficient is -50

Checking few numbers:

f(1)=(1)^{3}+8(1)^2+5(1)-50\\f(1)=1+8+5-50\\f(1)=-32\\Now \ putting \ x= 2 \\f(2)=(2)^{3}+8(2)^2+5(2)-50\\f(2)=8+8(4)+10-50\\f(2)=8+32+10-50\\f(2)=0

So, f(2)=0 which means x-2 is a factor of the given function. Now we will perform long division of x^3+8x^2+5x-50 by (x-2) to find other factors

The long division is shown in figure attached.

After long division we get: x^2+10x+25

The equation x^2+10x+25 can be further simplified as: (x+5)(x+5) or (x+5)^2

So, the factors of  f(x)=x^3+8x^2+5x-50 are (x-2)(x+5)(x+5)

3 0
3 years ago
Factor the polynomial:<br> wz -18 +6z -3w
alexira [117]

The answer is (z - 3) (w + 6)

8 0
2 years ago
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One number is 2 more than 3 times another. Their sum is 22. Find the numbers. 8, 14 5, 17 2, 20 4, 18 10, 12
xxTIMURxx [149]

9514 1404 393

Answer:

  (b)  5, 17

Step-by-step explanation:

You can try the answer choices easily enough.

  2 +3×8 ≠ 14

  2 +3×5 = 17 . . . . this choice works (5, 17)

  2 +3×2 ≠ 20

  2 +3×4 ≠ 18

  2 +3×10 ≠ 12

__

Or, you can solve the equation:

  x + (2 +3x) = 22

  4x = 20 . . . . . . . . subtract 2

  x = 5 . . . . . . . . . . divide by 4

The numbers are 5 and (22 -5) = 17.

5 0
2 years ago
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