Answer:
a) There is a 13% probability that a student has taken 2 or more semesters of Calculus.
b) 45% probability that a student has taken some calculus.
c) 87% probability that a student has taken no more than one semester of calculus.
Step-by-step explanation:
We have these following probabilities:
A 55% that a student hast never taken a Calculus course.
A 32% probability that a student has taken one semester of a Calculus course.
A 100-(55+32) = 13% probability that a student has taken 2 or more semesters of Calculus.
a) two or more semesters of Calculus?
There is a 13% probability that a student has taken 2 or more semesters of Calculus.
b) some Calculus?
At least one semester.
So there is a 32+13 = 45% probability that a student has taken some calculus.
c) no more than one semester of Calculus?
At most one semester.
So 55+32 = 87% probability that a student has taken no more than one semester of calculus.
Answer:
the factors of f(x)=x^3+8x^2+5x-50 are (x-2)(x+5)(x+5)
Step-by-step explanation:
We need to factorise the function 
If a number is a factor of this function than it must be completely divisible by last co-efficient. Our last co-efficient is -50
Checking few numbers:

So, f(2)=0 which means x-2 is a factor of the given function. Now we will perform long division of
by (x-2) to find other factors
The long division is shown in figure attached.
After long division we get: 
The equation
can be further simplified as: (x+5)(x+5) or (x+5)^2
So, the factors of f(x)=x^3+8x^2+5x-50 are (x-2)(x+5)(x+5)
The answer is (z - 3) (w + 6)
9514 1404 393
Answer:
(b) 5, 17
Step-by-step explanation:
You can try the answer choices easily enough.
2 +3×8 ≠ 14
2 +3×5 = 17 . . . . this choice works (5, 17)
2 +3×2 ≠ 20
2 +3×4 ≠ 18
2 +3×10 ≠ 12
__
Or, you can solve the equation:
x + (2 +3x) = 22
4x = 20 . . . . . . . . subtract 2
x = 5 . . . . . . . . . . divide by 4
The numbers are 5 and (22 -5) = 17.