Answer:
P(Coin landing heads and blue marble is randomly selected) = 3/20.
Step-by-step explanation:
In this question, two events simultaneously take place. First, all the probabilities have to be identified. It is mentioned that the coin is a fair coin, therefore the probabilities of all the outcomes associated with the coin tossing will be equal. Therefore:
P(Coin landing heads) = 1/2.
P(Coin landing tails) = 1/2.
There are a total of 3 blue + 4 green + 3 red = 10 marbles in the bag. Therefore:
P(Selected marble is blue) = 3/10.
P(Selected marble is green) = 4/10.
P(Selected marble is red) = 3/10.
Assuming that both the events are independent, the probabilities of both the events can safely be multiplied. Therefore:
P(Coin landing heads and blue marble is randomly selected) = 1/2 * 3*10 = 3/20.
Therefore, the answer is 3/20!!!
