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marysya [2.9K]
3 years ago
14

Suppose logbx = logcx, where b ≠ c. Then the value of x can be

Mathematics
1 answer:
horrorfan [7]3 years ago
3 0

Not A: We can't have x=0 because \log0 is undefined for a logarithm of any base.

B is true: \log1=0 for any base.

Not C: If x=b^c, then \log_bb^c=c, but \log_cb^c=c\log_bc which only reduces to c if \log_bc=1. This can only happen if b=c, however, but we've assumed otherwise.

Not D: The reasoning for C not being correct is enough to rule out this possibility.

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