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Phoenix [80]
2 years ago
9

Going to college can cost a lot! What are some costs of attending college? Come up with at least 3 different costs.

Mathematics
2 answers:
scoray [572]2 years ago
6 0
Buying books, your dorm and maybe a ride to get to school
Damm [24]2 years ago
5 0

Answer:

Housing/Dorms, Tuition and transportation

Step-by-step explanation:

You might be interested in
A video game store allows customers to rent games for 4.75 each. Customers can also buy a membership for $54 annually, and video
ankoles [38]
Answer:

24 video games

Step-by-step explanation:

Let x represent number of video games.
We have been given that a video game store allows customers to rent games for $4.75 each. So the cost of renting x video games would be 4.75x.

We are also told that customers can also buys a membership for $54 annually, and video games would only cost $2.50 each. The cost of renting x video games after membership would be 2.50x + 54

To find the number of video-games that will cost same for both options, we will equate both expressions as:

4.75x = 2.50x + 54
4.75x - 2.50x = 2.50x - 2.50x + 54


Therefore, a customer would have rent 24 video games in a year in order for the two options to be equal.
3 0
3 years ago
Quadrilateral ABCD is a square. if m
olganol [36]
The answer is B. 18

Explanation:

We know that a square has 4 right angles. A right angle is 90°.

5x° = 90°
5(18)° =90°
90°=90°

Hope this helps some
4 0
2 years ago
A rental car company charges $77. 50 per day to rent a car and $0. 14 for every mile
muminat

77.5d + .14m

m = 425

.14 * 425 = 59.5

77.5d + 59.5 ≤ 230

77.5d ≤ 170.5

d ≤ 170.5/77.5

d ≤ 2.2

if they only take payment for whole days, he has 2 whole days

6 0
2 years ago
Tan^2 A/1+cot^2 A + cot^2 A/1+tan^2 A=sec^2 A cosec^2 A-3
omeli [17]
\frac{tan^2x}{1+cot^2x}+\frac{cot^2x}{1+tan^2x}=sec^2x\ cosec^2x-3\\\\L=\frac{tan^2x(1+tan^2x)+cot^2x(1+cot^2x)}{(1+cot^2x)(1+tan^2x)}=\frac{tan^2x+tan^4x+cot^2x+cot^4x}{1+tan^2x+cot^2x+tanxcotx}\\\\=\frac{tan^2x+cot^2x+tan^4x+cot^4x}{1+tan^2x+cot^2x+1}=\frac{tan^2x+2+cot^2x+tan^4x-2+cot^4x}{tan^2x+cot^2x+2}

=\frac{(tanx+cotx)^2+(tan^2x-cot^2x)^2}{(tanx+cotx)^2}=\frac{(tanx+cotx)^2}{(tanx+cotx)^2}+\frac{(tan^2x-cot^2x)^2}{(tanx+cotx)^2}\\\\=1+\frac{(tanx-cotx)^2(tanx+cotx)^2}{(tanx+cotx)^2}=1+(tanx-cotx)^2\\\\=1+tan^2x-2tanx\ cotx+cot^2x=tan^2x+cot^2x+1-2\\\\=\left(\frac{sinx}{cosx}\right)^2+\left(\frac{cosx}{sinx}\right)^2-1=\frac{sin^2x}{cos^2x}+\frac{cos^2x}{sin^2x}-1=\frac{sin^4x+cos^4x}{sin^2x\ cos^2x}-1

=\frac{(sin^2x)^2+2sin^2x\ cos^2x+(cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{(sin^2x+cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{1}{sin^2x\ cos^2x}-\frac{2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1}{sin^2x}\cdot\frac{1}{cos^2x}-2-1\\\\=cosec^2x\cdot sec^2x-3=sec^2x\ cosec^2x-3=R
3 0
3 years ago
Please help I have searched this question and have not found it. I am bad at math and I'm taking a test and need answers so plea
Vanyuwa [196]

Answer:

C because 18-6=12

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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