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3 years ago

Lines A and B parallel lines cut by the transversal c. If the measure of angle 5 is 123, what is the measure of angle 1?

Mathematics

1 answer:

Jet001 [13]3 years ago

4 0

123. angle 1 would be the same as angle 5, seeing as the lines are parallel. 5&1 are both on top on lines A & B AND on the same side of transversal

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write the standard equation of a circle that is tangent to the x-axis with the center located at (2,4)

dmitriy555 [2]

Answer:

Step-by-step explanation:

radius=4 as it is tangent to x-axis.

y co-ordinate of center is 4 so radius=4

eq. of circle is (x-2)²+(y-4)²=4²

or x²-4x+4+y²-8y+16=16

or x²+y²-4x-8y+4=0

4 0

3 years ago

-2x + 5 (1 -7x ) =190

luda_lava [24]

The answer is x= -5 ...explained... -2x + 5 -35x= 190...-37x +5 = 190 ... now subtract 190-5 = 185... divide 185 by - 37 and get -5

8 0

3 years ago

Angle 1 and Angle 2 form a linear pair. If m41 = (5x + 9)® and m22 = (3x + 11)", find the measure of

MissTica

Answer:

2/23/140+50ismmm/50

148/'320"120+4640=%40=40

7 0

3 years ago

What is the value can u show work

Basile [38]

You would put 8 where x is and -10 where y is and then you will do -10 to the second power, which you will get 100 and so you will get 104. The answer is
D) 104

6 0

3 years ago

(3.8 x 10 ^ -6) x (2.37 x 10 ^ -3)<br><br> Enter the answer in science notification

Black_prince [1.1K]

Multiply the coefficients and the powers of 10 with each other:

$(3.8 \times 10^{-6}) \times (2.37 \times 10^{-3}) = (3.8\times2.37) \times (10^{-6} \times10^{-3})$

The numeric part simply yields

$3.8\times2.37 = 9.006$

As for the powers of 10, you have to add the exponents, using the rule

$a^b \times a^c = a^{b+c}$

So, we have

$10^{-6} \times10^{-3} = 10^{-6-3} = 10^{-9}$

So, the final answer is

$9.006\times 10^{-9}$

7 0

3 years ago