3 years ago

Given the two sets, which statement is true?

1 answer:

monitta3 years ago

6 0

I think it is 3 A but it is hard to know what the question is asking... but my logic is that 3 A is right because A = 1+2 = 3

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Θ is in Quadrant III and cos^2 0= 1/4

pychu [463]

I think you mean to say $\cos^2\theta=\dfrac14$ . If $\theta$ is in the third quadrant, then $\sin\theta$ and $\cos\theta$ . Recall that

$\sin^2\theta+\cos^2\theta=1\implies\sin\theta=\pm\sqrt{1-\cos^2\theta}$

We expect $\sin\theta$ to be negative, so we take the negative root. We end up with

$\sin\theta=-\sqrt{1-\dfrac14}=-\dfrac{\sqrt3}2$

We also know to expect $\cos\theta$ , so

$\cos\theta=\pm\sqrt{\dfrac14}\implies\cos\theta=-\dfrac12$

By definition, we have

$\cot\theta=\dfrac{\cos\theta}{\sin\theta}$

and so

$\cot\theta=\dfrac{-\frac12}{-\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

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2 years ago

What values are needed to make each expression a perfect square trinomial?

Ivahew [28]

Answer:

Step-by-step explanation:

x² + 2(x)(2) + 2²

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2 years ago