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3 years ago

Solve the inequality: 5x - 7 ≥ 3x + 9

Mathematics

2 answers:

Naddika [18.5K]3 years ago

5 0

Answer:

x ≥ 8

Step-by-step explanation:

Subtract 3x from both sides:

2x - 7 ≥ 9

Then add 7 to both sides:

2x ≥ 16, or

x ≥ 8

erastova [34]3 years ago

3 0

Answer:

x≥8

Step-by-step explanation:

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Tommy has 5 jars of marbles. Each jar is 2/3 filled with marbles. If Tommy decided to combine the marbles completely fill the ja

antoniya [11.8K]

Answer:

Step-by-step explanation:

to find this answer we will then have to do 5 x 2/3

since we our multiplying by a fraction we will then have to change the fraction to a decimal.

2/3 = 0.6

this will then give us the equation of 5 x 0.6

this will give us the sum of 3 jars that had were able to be filled woth marbles.

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3 years ago

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kherson [118]

Answer:

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Step-by-step explanation:

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3 years ago

6. Two observers, 7220 feet apart, observe a balloonist flying overhead between them. Their measures of the

MaRussiya [10]

Answer:

The ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

Step-by-step explanation:

Let's call:

h the height of the ballonist above the ground,

a the distance between the two observers,

$a_1$ the horizontal distance between the first observer and the ballonist

$a_2$ the horizontal distance between the second observer and the ballonist

$\alpha _1$ and $\alpha _2$ the angles of elevation meassured by each observer

S the area of the triangle formed with the observers and the ballonist

So, the area of a triangle is the length of its base times its height.

$S=a*h$ (equation 1)

but we can divide the triangle in two right triangles using the height line. So the total area will be equal to the addition of each individual area.

$S=S_1+S_2$ (equation 2)

$S_1=a_1*h$

But we can write $S_1$ in terms of $\alpha _1$ , like this:

$\tan(\alpha _1)=\frac{h}{a_1} \\a_1=\frac{h}{\tan(\alpha _1)} \\S_1=\frac{h^{2} }{\tan(\alpha _1)}$

And for $S_2$ will be the same:

$S_2=\frac{h^{2} }{\tan(\alpha _2)}$

Replacing in the equation 2:

$S=\frac{h^{2} }{\tan(\alpha _1)}+\frac{h^{2} }{\tan(\alpha _2)}\\S=h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})$

And replacing in the equation 1:

$h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})=a*h\\h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}$

So, we can replace all the known data in the last equation:

$h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}\\h=\frac{7220 ft}{(\frac{1 }{\tan(35.6)}+\frac{1}{\tan(58.2)})}\\h=3579,91 ft$

Then, the ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

6 0

3 years ago

The reasons as well as the answer

Radda [10]

Answer:

x = 46, y = 67

Step-by-step explanation:

x = ∠ AEC = 46 ( alternate angles )

Since Δ ACE is isosceles then the base angles are congruent, then

y = $\frac{180-46}{2}$ = $\frac{134}{2}$ = 67

4 0

3 years ago

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Suppose there is a simple index of two stocks - stock A and stock B. Stock A

MissTica

Answer:

I think its B but u could wait for another answer

Step-by-step explanation:

4 0

3 years ago

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