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sergeinik [125]
4 years ago
14

4 times 10a . 2b . 7 c . 40d .97​

Mathematics
2 answers:
leonid [27]4 years ago
4 0

Answer:

40

Step-by-step explanation:

      10

x       4

    =40

Simora [160]4 years ago
4 0

Answer:

<em>4*10 = C. 40</em>

Step-by-step explanation:

<em>Add 10 4 times and get 40!!</em>

<u><em>SIMPLE HOPE IT HEPLS PLEASE MARK BRAINLIST!!</em></u>

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The random numbers below represent 15 trials of a basketball simulation conducted using a spinner numbered 0–8. 76645, 46757, 28
mote1985 [20]

Answer: Option D.

Step-by-step explanation:

Out of the 15 simulations, the number with a 1 in them is 7. (are the sets of 5 shots that have at least one 3-pointer)

So out of 15 sets, 7 of them have at least one 3-point in them.

the experimental probability is p = 7/15.

So the correct option is D.

4 0
3 years ago
In how many ways can 15 people be divided into two groups, one group with 10 and the other with 5 people?
viktelen [127]

Answer:

Step-by-step explanation:

Given that there are 15 people and they should be divided into two groups one with 10 and the other with 5 people.

First group 10 persons can be selected from 15 in 15C10 ways.

Remaining 5 would automatically be put in group 2.

Hence no of ways = 15C5 =\frac{15!}[10!5!} \\=3003

5 0
3 years ago
Consider the radical equation = c + 2. Which statement is true about the solutions c = 3 and c = –6?
Phantasy [73]
The inside of the radical must be greater than or equal to zero. When you plug in c=3, the answer is 5 >0. When c=-6, -4 <0. Therefore c=3 is true.
6 0
3 years ago
Read 2 more answers
Use Definition 7.1.1, DEFINITION 7.1.1 Laplace Transform Let f be a function defined for t ≥ 0. Then the integral ℒ{f(t)} = ∞ e−
poizon [28]

f(t)=\begin{cases}\cos t&\text{for }0\le t

The Laplace transform is then

\mathcal L_s\{f(t)\}=\displaystyle\int_0^\infty f(t)e^{-st}\,\mathrm dt=\int_0^\pi e^{-st}\cos t\,\mathrm dt

Let I denote the integral we want to compute. Integrating by parts, setting

u=e^{-st}\implies\mathrm du=-se^{-st}\,\mathrm dt

\mathrm dv=\cos t\,\mathrm dt\implies v=\sin t

gives

\displaystyle I=e^{-st}\sin t\bigg|_{t=0}^{t=\pi}+s\int_0^\pi e^{-st}\sin t\,\mathrm dt

Integrate by parts again, setting

u=e^{-st}\implies\mathrm du=-se^{-st}\,\mathrm dt

\mathrm dv=\sin t\,\mathrm dt\implies v=-\cos t

Then

\displaystyle I=e^{-st}\sin t\bigg|_{t=0}^{t=\pi}+s\left(-e^{-st}\cos t\bigg|_{t=0}^{t=\pi}-s\int_0^\pi e^{-st}\cos t\,\mathrm dt\right)

I=e^{-st}(\sin t-s\cos t)\bigg|_{t=0}^{t=\pi}-s^2I

(s^2+1)I=s(e^{-\pi s}+1)

I=\dfrac s{s^2+1}(e^{-\pi s}+1)

7 0
4 years ago
What is the value of x?<br><br> Enter your answer in the box.<br><br> x =
sdas [7]
Hello!

A straight line measures to 180°

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180 = 134 + x

Subtract 134 from both sides

46 = x

The answer is 46°

Hope this helps!
7 0
3 years ago
Read 2 more answers
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