In order to solve this problem, we can use the Pythagorean Theorem, which is $c^2 = a^2 + b^2$ . Since the Pythagorean Theorem would find only half of the length of x, we'll need to double it in the end.

First, let's plug in what we know to the Pythagorean Theorem: $2.1^2 = 1.4^2 + b^2$

Next, we'll simplify to that $b^2$ is by itself:

$b^2 = 2.45$

Then, we'll find the square root of 2.45, multiply that by 2 and round to the nearest tenth:

$2(\sqrt{2.45} ) = 3.1$

Therefore, x = 3.1 ft.

How to round to the nearest tenth:

In a decimal, the tenth is the first number after the decimal point. To round to the tenth, if the number in the hundredth place is less than 5, you keep the number as it is, but if the number in the hundredth place is more than 5, you increase the number in the tenth place by 1.

Hope this helps!! :)

6 0

3 years ago

leonhard wants to place a triangular-based cabinet in the corner of his rectangle-shaped living room. the triangular base has a

Georgia [21]

The answer is $x = \frac{-7+ \sqrt{193} }{4}$ .

There is very similar question on Brainly, in which dimensions of the living room are given (20 feet, 30 feet).
So, knowing this, we first need to calculate how much 6% of the living room is.
The area of the living room is 600 square feet, since it is rectangle-shaped:
P = a * b = 200 feet * 30 feet = 600 square feet.

6% of 600 square feet is 36 square feet:
600 square feet : 100% = A : 6%
A = 600 * 6 / 100 = 36 square feet

The area of the triangular-based cabinet (A) is $A = \frac{a*h}{2}$ , where a is the base, and h is the height of the triangle.
It is given:
A = 36
a = 2x + 3
h = 3x + 6

Now, let's implement this to the formula $A = \frac{a*h}{2}$ :
$36 = \frac{(2x+3)(3x+6)}{2}$
⇒ $36*2=6 x^{2} +12x+9x+18$
$72=6 x^{2} +21x+18$

Let's both sides divide by 3:
$24=2 x^{2} +7x+6$
⇒ $2 x^{2} +7x-18=0$

This is the quadratic formula ( $a x^{2} +bx+c=0$ ) for which
$x = \frac{-b+\sqrt{b^{2} -4ac} }{2a}$ or
 $x = \frac{-b-\sqrt{b^{2} -4ac} }{2a}$ .
We will use only $x = \frac{-b+\sqrt{b^{2} -4ac} }{2a}$ , because the length cannot have negative value.

From the equation $2 x^{2} +7x-18=0$ , we know that
a = 2
b = 7
c = -18

Thus, $x = \frac{-7+ \sqrt{193} }{4}$ :
 $x= \frac{-b+ \sqrt{ b^{2} -4ac} }{2a} = \frac{-7+ \sqrt{ (7)^{2} -4*2*(-18)} }{2*2} = \frac{-7+ \sqrt{49+144} }{4} = \frac{-7+ \sqrt{193} }{4}$

4 0

3 years ago