6y + 12 = 3y - 3
Subtract 3y on both sides
3y + 12 = -3
Subtract 12 on both sides
3y = -15
Divide by 3 on both sides
y = -5
The remainder theorem says that the remainder upon dividing a polynomial
by a linear polynomial
is the same as the value of
at
. Dividing by any linear polynomial will always result in the following:
where
and
are also polynomials. Taking
, the term involving
vanishes, so that
is exactly the remainder upon dividing.
Via synthetic division, we have
... | 2 -9 7 -5 11
4 | 8 -4 12 28
- - - - - - - - - - - - - - - - - -
... | 2 -1 3 7 39
which translates to
that is, we're left with a remainder of 39.
Via the remainder theorem, we have
as expected.
Since this is a linear question in y=mx+b form, and where m is the slope of the line and b is the y-intercept....
The slope in this problem is 2/3
And y intercept is -1
So you would graph the point -1 on y axis then go up 2/3 since it’s positive( go up 2 over 3)
There are a total of 8 balls
The probability of drawing a white ball is 4/8 on the first draw.
If you replace the ball then the probability will still be 4/8 for a white ball, since these events are independent of each other you multiply 4/8 x 4/8 = 16/64 or 1/4 then the probability of drawing at least 1 red ball with replacement is 1 - 1/4 = 3/4
Now without replacement:
the probability of drawing a white ball is 4/8 since you don't replace the ball then the probability of drawing a white ball the second time is 3/7 again multiply these two probabilities: 4/8 x 3/7 = 12/56 the the probability of drawing at least 1 red ball is 1- 12/56 = 44/56 or 11/14
22 / (9 + 2) =
22 / 11 =
2 <==