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vovikov84 [41]
3 years ago
9

-6(m - 828) = -72 solve for m m=___

Mathematics
2 answers:
Naily [24]3 years ago
7 0

Answer:

Step-by-step explanation:

Here you go mate

Use PEMDAS

Parenthesis

Exponent

Multiplication

Division

Addition

Subtraction

Step 1

-6(m-828)=-72  Equation/Question

Step 2

-6(m-828)=-72  Remove parenthesis

-6m+4968=-72

Step 3

-6m+4968=-72  Subtract 4968 from sides

-6m=-5040

Step 4

-6m=-5040  Divide sides by 6

answer

m=840

Hope this helps

nydimaria [60]3 years ago
4 0

Answer:

m= 840

Step-by-step explanation:

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Answer:

(x+1) (x-1) (x+2) (x-2)

Step-by-step explanation:

<u>Let u = x^2</u>

= u^2 - 5u + 4

<u>(Factor u^2 - 5u + 4)</u>

= (u-1) (u-4)

<u>Substitute back u = x^2</u>

= (x^2 -1 ) (x^2 - 4)

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= (x+1) (x-1) (x+2) (x-2)

Hope this helped... :)

If you need to see the work for yourself, copy/paste this link

https://www.symbolab.com/solver/factor-calculator/factor%20x%5E%7B4%7D%20%E2%88%92%205x%5E%7B2%7D%20%2B%204%20

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3 years ago
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G two samples, one of size 14 and the second of size 13, are selected to test the difference between two population means. how m
vovikov84 [41]

Note :- If sample size n > 30 OR Population standard deviation σ is given then We use Z test.

If sample size n < 30 AND Population standard deviation σ is unknown then we use t test.

In this question we are not given Population standard deviations σ1 and σ2.

Also n1 = 14 and n2 = 13 both sample sizes are LESS than 30.

Therefore we use t test.

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then Degrees of freedom = n1 + n2 - 2 = 14 + 13 - 2 = 25.

(kindly find the image attached with this solution)

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Step-by-step explanation:

negative / negative = positive

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Identify the three similar right triangles in the given diagram.
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Answer:

B. ΔABD, ΔADC, ΔDBC

Step-by-step explanation

Step -1 In ΔABD and ΔADC (from figure).

∠DAB=∠CAD (common in both triangles) ,

∠DBA=∠CDA =90 degree, and

∠BDA=∠DCA (rest angle of the two triangles).

therefore ΔABD similar to ΔADC (by AAA similarity theorem).

Step -2 In ΔDBC and ΔADC (from figure).

∠DCB=∠ACD (common in both triangles) ,

∠DBC=∠ADC =90 degree, and

∠CDB=∠CAD (rest angle of the two triangles).

therefore ΔDBC similar to ΔADC (by AAA similarity theorem).

Step -3 In ΔABD and ΔDBC (from figure).

∠BDA=∠BCD (because , ∠ACD=ADB from stap-1 and ∠ACD=∠BCD from figure) ,

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therefore ΔABD similar to ΔDBC (by AAA similarity theorem).

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blue with green is 5/10 green and red 3/10 both red 2/10 both blue 4/10

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