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2 years ago

Ms. Florina buys a bag of different-colored rubber bands. She randomly selects a rubber

Mathematics

2 answers:

nadezda [96]2 years ago

8 0

Answer:18/25 1/5 14/25

Step-by-step explanation:

Alika [10]2 years ago

4 0

Answer:

18/25 1/5 14/25

Step-by-step explanation:

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Log2(62)<br> in natural logarithm

Blizzard [7]

Answer:

Step-by-step explanation:

Use the change-of-base rule.

log₂(62) = ln(62)/ln(2)

8 0

3 years ago

A rectangle as the width of 9 units and length of 40 units. What is the length of the diagonal?

Kitty [74]

Answer:

the Diagonal is 41 units

Step-by-step explanation:

Since the sides of a rectangle, to be a rectangle, meet at 90° we use Pythagorean Theorem a² + b² = c²

Width and Length are the legs and the diagonal is the hypotenuse

9² + 40² = c²

81 + 1600 = c²

1681 = c²

√1681 = √c²

41 = c

3 0

3 years ago

What is the converse of r->(~q v p)

alexira [117]

Answer:

$r => (\neg q \ \lor p) \ \equiv \ q \ \land \ \neg p => \neg r$

Step-by-step explanation:

In general, remember that the converse of $a => b$ is $\neg b => \neg a$ , therefore in this case $a = r \ \ , b = \neg q \ \lor p$

so $r => (\neg q \ \lor p) \ \equiv \ q \ \land \ \neg p => \neg r$

8 0

2 years ago

A large jar contains 1380 coins. The result of 40 coins pulled at random from the jar is given below.

vredina [299]

Answer:IS B OR D BUT I SAY D

Step-by-step explanation:

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3 years ago

Read 2 more answers

Shipping rates for Company A and Company B are shown in the tables below. Which company has shipping rates that you can represen

meriva

Company B; the ratios of cost to weight are equivalent.

Step-by-step explanation:

Step 1:

In the equation, $y=kx$ k is the constant of proportionality.

If the values are in accordance with $y=kx$ , the values of k will be constant for all the values.

So we determine the values of k for both the companies and see which has a constant k.

If $y=kx, k = \frac{y}{x}$ . In these tables, y is the total cost and x is the weight in lbs.

Step 2:

For company A,

when $y=10.55, x=1, k = \frac{10.55}{1} = 10.55,$

when $y=10.85, x=2, k = \frac{10.85}{2} = 5.425,$

when $y=11.15, x=3, k = \frac{11.15}{3} = 3.71666.$

For company B,

when $y=2.75, x=1, k = \frac2.75}{1} = 2.75,$

when $y=5.50, x=2, k = \frac{5.50}{2} = 2.75,$

when $y=8.25, x=3, k = \frac{8.25}{3} = 2.75.$

So company B has a constant value of $k=2.75$ .

3 0

2 years ago