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levacccp [35]
3 years ago
8

2. Given that a = 7, b = 5 and c = 5. Find the square root of 3a + 2b + c

Mathematics
1 answer:
ollegr [7]3 years ago
5 0

Step-by-step explanation:

3a + 2b + c  =  3(7) + 2(5) + 5 \\  = 21 + 10 + 5 \\  = 36 \\  \sqrt{3a + 2b + c}  =  \sqrt{36}  \\  = 6

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Janice's mother gave her ten-dollar bill to buy five pounds each bananas and apples at the grocery store. When she got there she
lakkis [162]

Buying apples and bananas with $10


5 pounds of bananas so

5 x .80 = $4

5 pounds of apples so

5 x 1.40 = $7


$7 + $4 = $11

she only has $10

$11 - $10 =  - 1,00


so no. she will not recieve any change because she doesnt havew enough money

6 0
3 years ago
The depth of a scuba diver can be modeled by the equation d 0.5t (3.5t- 28.25), where d is the depth in meters of the diver and
user100 [1]
We know that

using a graph tool
see the attached figure

<span>The diver reaches the surface when d = 0
</span>so
<span>0.5t (3.5t- 28.25)=0---------> the solution is
0.5t=0--------> t=0
and
</span><span>(3.5t- 28.25)=0----------> 3.5t=28.25--------> t=28.25/3.5--------> t=8.07 minutes
</span><span>

the time it takes for the diver to reach the surface is when the depth is zero
the time is 8 minutes

the answer is 
8 minutes</span>

8 0
3 years ago
Given: P is a point on the perpendicular bisector, I of MN.<br> Prove: PM = PN
Hatshy [7]

Answer:

Step-by-step explanation:

I can't make specific statements about the proof because the midpoint is missing.

Givens

There are two right angles created by where the perpendicular bisector meats MN. Both are 90 degrees.

MN is bisected by the point on MN where the perpendicular meets MN

The Perpendicular Bisector is is common to both triangles.

Therefore the two triangles are congruent by SAS

PM = PN                Parts contained in Congruent triangles are congruent.

5 0
3 years ago
Limit of x^2-81/x+9<br> As x goes toward -9
Semmy [17]
Hello,

Use the factoration

a^2 - b^2 = (a - b)(a + b)

Then,

x^2 - 81 = x^2 - 9^2

x^2 - 9^2 = ( x - 9).(x + 9)

Then,

Lim (x^2- 81) /(x+9)

= Lim (x -9)(x+9)/(x+9)

Simplity x + 9

Lim (x -9)

Now replace x = -9

Lim ( -9 -9)

Lim -18 = -18
_______________

The second method without using factorization would be to calculate the limit by the hospital rule.

Lim f(x)/g(x) = lim f(x)'/g(x)'

Where,

f(x)' and g(x)' are the derivates.

Let f(x) = x^2 -81

f(x)' = 2x + 0
f(x)' = 2x

Let g(x) = x +9

g(x)' = 1 + 0
g(x)' = 1

Then the Lim stay:

Lim (x^2 -81)/(x+9) = Lim 2x /1

Now replace x = -9

Lim 2×-9 = Lim -18

= -18




7 0
3 years ago
How do you evaluate 3x+8 when x=2?
alisha [4.7K]
Plug the x in :)

3(2) + 8
6 + 8
=14
6 0
3 years ago
Read 2 more answers
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