Answer:
We need the directions. Once provided I will then edit this.
Explanation:
Answer:
B. Gametophytes of seedless vascular plants
Answer:
Alleles for feather colour exhibit incomplete dominance or co-dominance.
50% gray offspring + 50% black offspring
Explanation:
<em>It means that the alleles for feather colour in the hen exhibit incomplete dominance or co-dominance over one another.</em>
Assuming the allele for white colour is B, white colour will be b while the heterozygote Bb gives the gray phenotype.
Gray rooster + gray hen = 15 gray chicks, 6 black chicks and 8 white chicks.
15:6:8 is roughly 2:1:1 which is phenotypic ratio obtainable from crossing two heterozygous individuals as pointed out by Mendel.
Bb x Bb = 1BB, 2Bb, and 1bb
Crossing the gray rooster (Bb) with a black hen (bb):
Bb x bb = Bb, Bb, bb, and bb
= 2Bb (gray):2bb (black)
50% of the offspring will be gray while the remaining 50% will be black.
Answer:
not really a pro at health but I can try! I would say have a different diet while healing and stay home from soccer and let it heal. he should go to therapy daily for updates to see if his arm is healing or not. he should not take to much pressure onto his arm.
Explanation:
The answer will be A because mitosis usually separate the sister chromatids to sister chromosomes to form two diploid cells. In meiosis, the goal is to have four haploid cells. To form that, cells need to undergo cell division two times. In the case of meiosis I, sister chromatids stay joined together until it reaches meiosis II. Then, the sister chromatids will separate starting at anaphase II in meiosis II. For example, if you start with 92 chromosomes (46 chromatids) during meiosis I, at meiosis II you will have two cells with 46 chromosomes (23 chromatids). By the end of meiosis II, you should form 4 haploid cells that contains 23 chromosomes.
